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Any number that you choose can be the nth number for any given n. It is easy to find a rule based on a polynomial of order 4 such that the first four numbers are as listed in the question and the nth is the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest soution, based on a polynomial of order 3, is
t(n) = (n^2 - 3*n + 2)/2 or (n - 1)*(n - 2)/2 for n = 1, 2, 3, ...
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What is the nth term for 0 -1 -2 -3 -4?
n - 1
What is the nth term of 3 1 -1 -3 -5?
The nth term is: 5-2n
What is the simple formula for the nth term of the arithmetic sequence 7 3 -1 -5 -9?
7 - 4n where n denotes the nth term and n starting with 0
What is the nth term for 0 1 1 2 3 5 8 13?
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
What is the nth term to -6 -3 0 3 6?
n-9+3
What is the nth term for 0 -1 -2 -3 -4?
n - 1
What is the nth term of 3 1 -1 -3 -5?
The nth term is: 5-2n
What is the simple formula for the nth term of the arithmetic sequence 7 3 -1 -5 -9?
7 - 4n where n denotes the nth term and n starting with 0
What is the nth term for 0 1 1 2 3 5 8 13?
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
What is the nth term to -6 -3 0 3 6?
n-9+3
What is nth term for 0 3 8 15 24?
0,3,8,15,24,27,32,41
What is the nth term of this sequence 3 5 7 9 11?
The nth term of the sequence is 2n + 1.
What is the nth term of 1 -3 -7 -11 and -15?
It is: nth term = 5-4n and so the next term will be -19
What is the nth term in 1 3 7 11 15?
If you mean -1 3 7 11 15 then the nth term is 4n-5 and so the next term will be 19
What is the nth term in the sequence 3 7 11 15?
The nth term is 4n-1 and so the next term will be 19
What is the pattern for 0 0 1 3 6?
The pattern for the sequence 0 0 1 3 6 is that each term is obtained by adding the previous term multiplied by its position in the sequence (starting from 1). In other words, the nth term is given by n*(n-1)/2.
What is the nth term for the sequence 1 0 3 8?
an^3 bn^2+cn+d=E(n) where E(n) is the value of the nth term and a,b, c and d are constants. So we have: a+b+c+d=1 8a+4b+2c+d=0 27a+9b+3c+d=3 64a+16b+4c+d=8 Then work it out from there. Assuming the first term was supposed to be -1 (minus 1) not 1 (plus one), then the nth term is given by: tn = n2 - 2n
