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What orkin number 1 pest in America?
Orkin says the number one pest is Ants.
What is the number 1 household pest?
According to Orkin the #1 Pest problem in America are Ants.
If you have a fair coin and number cube find the theoretical probability of the landing of heads and the rolling of three?
Prob of heads = 1/2 Prob of 3 = 1/6 Prob of both = 1/2 x 1/6 = 1/12
What is the chance of getting an even number when you toss a number cube 10 times?
It is 1 - Prob(No even numbers in 10 throws) = 1 - [Prob(Not an even number)]10 = 1 - (1/2)10 = 1 - 1/1024 = 1023/1024 or 0.9990 So you are almost certain to get an even number.
When rolling 2 dice what is the probability of rolling a number greater than 2?
Prob(Rolling a number greater than 2) = 1 - Prob(Not rolling a number greater than 2 on either die) = 1 - Prob(Rolling a number less than or equal to 2 on both dice) = 1 - Prob(Rolling a number less than or equal to 2 on a die)2 = 1 - (1/3)2 = 8/9
A Fibonacci die has the numbers1 1 2 3 5 and 8on it if two are thrown what is the probability that the number on one die is larger than the number on the other?
Prob( Number on one die is larger than that on the other) = 1 - Prob(Number on both dice is the same). If the two 1s are distinguished as 1 and 1', then the favourable outcomes are (1,1), (1,1'), (1',1), (1',1'), (2,2), (3,3), (5,5) and (8,8) - eight of them in all. So 1 - Prob(Number on both dice is the same) = 1 - 8/36 = 1 - 2/9 = 7/9
What is the probability of rolling first an odd number then an even number with one fair die?
Prob = 1/2 * 1/2 = 1/4
How do you find expected number of coin toss?
expected number = number of toss time 1/6. each face has prob to shown equally 1/6.
What is the probability of rolling a sum of 7 or a sum of 11?
If two fair number cubes are rolled, the answers are: Prob(7) = 6/36 = 1/6 Prob(11) = 2/36 = 1/18.
What is the probability that a cube will land on 4. A coin will land on heads?
Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.
There is a 80 percent chance of rain today and a 50 percent chance of rain tomorrow If the two events are independent what is the probability that it will rain today or tomorrow?
It is 1 - prob(it does not rain today and tomorrow)= 1 - prob(it does not rain today)*prob(it does not rain tomorrow) = 1 - [1- prob(it does rain today)]*[1 - prob(it does rain tomorrow)] = 1 - [1 - 0.8]*[1 - 0.5] = 1 - 0.2*0.5 = 1 - 0.1 = 0.9
Would someone help guide you about how to do Probability Math -See Discussion Area for more detailed information?
The first step is to create the write out the probability space. For each possible product, list the values on each die that will give that product. Each such outcome has a probability of 1/36 and so you can calculate the probability of each of the numbers on the card as follows: 1: (1,1) prob = 1/36 2: (1, 2), (2, 1) prob = 2/36 3: (1, 3), (3, 1) prob = 2/36 4: (1, 4), (2, 2), (4, 1) prob = 3/36 5: (1, 5), (5, 1) prob = 2/36 6: (1, 6), (2, 3), (3, 2), (6, 1) prob = 4/36 8: (2, 4), (4, 2) prob = 2/36 9: (3, 3) prob = 1/36 10: (2, 5), (5, 2) prob = 2/36 12: (2, 6), (3, 4), (4, 3), (6, 2) prob = 4/36 15: (3, 5), (5, 3) prob = 2/36 16: (4, 4) prob = 1/36 18: (3, 6), (6, 3) prob = 2/36 20: (4, 5), (5, 4) prob = 2/36 24: (4, 6), (6, 4) prob = 2/36 25: (5, 5) prob = 1/36 30: (5, 6), (6, 5) prob = 2/36 36: (6, 6) prob = 1/36
