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What is the number of distinguishable permutation of the letters in the word September?
Wiki User
∙ 10y ago
September has 9 letter, of which one appears 3 times.
So the number of distinct permutations is 9!/3! = 120,960
Wiki User
∙ 10y ago
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Find the number of distinguishable permutations of the letters in the word manatee?
Take the total number of letters factorial, then divide by the multiple letters factorial (a and e). 7! / (2!*2!) or 1260.
Find the number of distinguishable permutations of the letters in the word Cincinnati?
There are ten letters in the word. The total number of possible permutations is(10) x (9) x (8) x (7) x (6) x (5) x (4) x (3) x (2) = 3,628,800But the two 'c's can be arranged in either of 2 ways with no distinguishable change.Also, the three 'i's can be arranged in any of (3 x 2) = 6 ways with no distinguishable change.And the three 't's can be arranged in any of (3 x 2) = 6 ways with no distinguishable change.So the total number of possible permutations can be divided by (2 x 6 x 6) = 72, the number oftimes each distinguishable permutation occurs with different and indisnguishable arrangementsof 'c', 'i', and 't'.We're left with(10) x (9) x (8) x (7) x (...) x (5) x (...) x (...) x (2) = (3,628,800/72) = 50,400 distinguishable arrangements.
Find the number of distinguishable permutations of letters in the word appliance?
The distinguishable permutations are the total permutations divided by the product of the factorial of the count of each letter. So: 9!/(2!*2!*1*1*1*1*1) = 362880/4 = 90,720
What is the permutation of 5?
Permutations are the different arrangements of any number of objects. When we arrange some objects in different orders, we obtain different permutations.Therefore, you can't say "What is the permutation of 5?". To calculate permutations, one has to get the following details:The total number of objects (n) (necessary)The number of objects taken at a time (r) (necessary)Any special conditions mentioned in the question (optional).
What is a general formula for the permutation nPr in terms of n and r For instance if you have the permutation nP1 how do you find n?
Permutation Formula A formula for the number of possible permutations of k objects from a set of n. This is usually written nPk . Formula:Example:How many ways can 4 students from a group of 15 be lined up for a photograph? Answer: There are 15P4 possible permutations of 4 students from a group of 15. different lineups
What is the number of distinguishable permutations of the letters in the word GLASSES?
The solution is count the number of letters in the word and divide by the number of permutations of the repeated letters; 7!/3! = 840.
What do you use to compute the total number of a 4-letter names with nonrepeating letters?
permutation without replacement
Find the number of distinguishable permutations of the letters in the word manatee?
Take the total number of letters factorial, then divide by the multiple letters factorial (a and e). 7! / (2!*2!) or 1260.
Find the number of distinguishable permutations of the letters in the word Cincinnati?
There are ten letters in the word. The total number of possible permutations is(10) x (9) x (8) x (7) x (6) x (5) x (4) x (3) x (2) = 3,628,800But the two 'c's can be arranged in either of 2 ways with no distinguishable change.Also, the three 'i's can be arranged in any of (3 x 2) = 6 ways with no distinguishable change.And the three 't's can be arranged in any of (3 x 2) = 6 ways with no distinguishable change.So the total number of possible permutations can be divided by (2 x 6 x 6) = 72, the number oftimes each distinguishable permutation occurs with different and indisnguishable arrangementsof 'c', 'i', and 't'.We're left with(10) x (9) x (8) x (7) x (...) x (5) x (...) x (...) x (2) = (3,628,800/72) = 50,400 distinguishable arrangements.
In how many ways can all the letters in the word mathematics be arranged in distinguishable permutations?
The word mathematics has 11 letters; 2 are m, a, t. The number of distinguishable permutations is 11!/(2!2!2!) = 39916800/8 = 4989600.
Find the number of distinguishable permutations of the letters honest?
It is 6! = 6*5*4*3*2*1 = 720
What is the permutation of 7?
There can be only one permutation of a single number: so the answer is 7.
Find the number of distinguishable permutations of the letters in the word hippopotamus?
First of all, find the total number of not-necessarily distinguishable permutations. There are 12 letters in hippopotamus, so use 12! (12 factorial), which is equal to 12 x 11x 10 x9 x8 x7 x6 x5 x4 x3 x2 x1. 12! = 479001600.Then count the of each letter and calculate how many permutations of each letter can be made. For example, here is 1 h, so there is 1 permutation of 1 h.H 1I 1P 60 2T 1A 1M 1U 1S 1Multiply these numbers together. 1 x1 x6 x2 x1 x1 x1 x1 x1 = 12Divide 12! by this number. 479001600 / 12 = 39,916,800 Distinguishable Permutations.
How may distinguishable permutations are possible with all the letters of the word ellises?
We can clearly observe that the word "ellises" has 7 letters and three pairs of letters are getting repeated that are 'e','l' and 's'. So, Number of distinguishable permutations = 7!/(2!2!2!) = 7 x 6 x 5 x 3 = 630.
What month has the same number of letters in its name as the number?
september
What number of permutation of the letters in the word smart?
For the first letter, you can have any of 5 choices. Then for the next, you can have any of four. Then for the next, three and so on. Thus the number of permutations can be calculated by 5x4x3x2x1. Doing this gives 120. Therefore the number of permutations of the letters in the word smart is 120.
What is the symbol for permutation?
nPrwhere:n number of objectsr is number of arrangements
