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5 sides and it is a regular pentagon

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Q: What is the number of sides of a regular polygon if one interior angle measures 108?
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What is the number of sides of a regular polygon if one interior angle measures 90?

A four-sided regular polygon (square or rectangle) has 900 interior angles.


What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?

The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.


As the number of sides in a regular polygon increases what happens to the measure of an interior angle?

As the number of sides in a regular polygon increases, the angle increases. This occurs as a function where each interior angle measures (180*(n-2)) / n, where n is the number of sides.


What is the number of sides of a re gular polygon if one interior angle measures 108?

A polygon with interior angle measures of 108 would be a pentagon


Which regular polygon has interior angles with measures greater than 130?

For the interior angle of a regular polygon to be greater than 130° then the exterior angle must be less than 50°. The exterior angles of a regular polygon total 360°. 360/50 = 7.2 ....this needs to be rounded up to the next whole number. Therefore a regular polygon with 8 or more sides has interior angles measuring 130° or greater.


What is the number of sides of a regular polygon if one angle measures 140 degrees?

Since the interior angle measure of the regular polygon is 140⁰, its exterior angle measure is 180⁰ - 140⁰ = 40⁰. Since the sum of the exterior angle measures is 360⁰, the polygon has 360⁰/40⁰ = 9 sides.


What is the sum of the interior angle measures of a 21-sided polygon?

The sum of the interior angles of a polygon is 2n - 4 right angles where n is the number of sides. When n = 21 then 2n - 4 = 42 - 4 = 38 right angles = 38 x 90 = 3420°. NOTE : If the polygon is a regular polygon then each interior angle measures 3420 ÷ 21 = 162.86°.


How do you find a number of sides of a polygon with the measure of its interior angle?

If its a regular polygon then 180-interior angle and divide the answer into 360 which will give the number of sides of the polygon.


If each interior angle of a regular polygon measures 170 degrees what is the total number of sides in the polygon?

170n = 180n - 360 so 10n = 360 so n = 36


If the measure of each interior angle of a regular polygon is 176 what is the number of sides of the polygon?

The equation for finding the interior angle measures of a regular n-gon is (n-2)*180/n. Thus, if this is set equal to 176 and solved for n, n is found to be 90. Therefore, a regular polygon with each interior angle measure equal to 176, has 90 sides.


Work out the number of sides of a regular polygon with the interior angle of 178?

If each interior angle is 178 degrees then the regular polygon will have 180 sides.


What is the number of sides of a regular polygon if one angle measures 172 degrees?

If one interior angle measures 172° then the corresponding exterior angle measures 180 - 172 = 8°. The number of sides = 360 ÷ 8 = 45.