There's no way to answer that, because it can be a different number in every situation.
It can never be greater than ' 1 ', but the actual number depends on how squiggly the
route is between the starting point and the ending point.
1 is to 1
There's no firm relationship between the magnitudes of distance and displacement, except that displacement can never be greater than distance. So if you're looking for a ratio, I guess (distance)/(displacement) = or > 1
Distance input --------------- = Speed Ratio Distance output The distance input divided by the distance output equals the Speed Ratio.
12:3
It's not always the same number. But whatever that ratio happens to be in a specific situation, it can never be less than ' 1 '.
1 is to 1
The ratio is 1.
There's no firm relationship between the magnitudes of distance and displacement, except that displacement can never be greater than distance. So if you're looking for a ratio, I guess (distance)/(displacement) = or > 1
After traversing 1/2 of a circular track with radius 'R', the body has effectively moved from one end of a diameter to the other end of the same diameter. The distance traveled is 1/2 the circumference = (pi)D/2 = (pi)R. The displacement is D = 2R. The ratio of displacement to distance = (2R)/(piR) = 2/pi= 0.63662 (rounded), independent of 'R'.
The technical answer is that displacement is the vector sum of the distances. An example to illustrate the difference in less technical terms, distance travelled in one direction added to the same distance in the opposite direction will result in the total distance being twice the distance of each leg but the total displacement is 0.
Example: There are 6 fish and 19 dogs. The numerical ratio of fish to dogs is 6/19 .
speed is the ratio of the distance an object moves per time unit (seconds,minutes hours)
These have to do with the hydraulic density. In automobile, the density increases therefore making the hydraulic ratio to displace more than any hydraulic ratio in a displacement.
ratio=numerical number
Distance input --------------- = Speed Ratio Distance output The distance input divided by the distance output equals the Speed Ratio.
There isn't a set displacement to horsepower ratio - hence, horsepower can't be determined by displacement alone.
It is ratio.