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Average velocity is total distance by total time .

let us calculate velocity at the end of 6 seconds.

v=vo+at

v= 0+1.7*6

v=10.2 m/sec

distance travelled by object in six seconds

x= vot+1/2at2

x=0+.5(1.7)(62)

x=30.6 m

the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity

x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs.

x=10.2*9=91.8

Again . . average velocity is total distance by total time.

Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s

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Q: What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
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