There are infinitely many ordered pairs that satisfy this equation. Supply any value for x, then solve for y to get the other part of the pair.

The ordered pair is (1, 1).

The ordered pair is (5, 4).

No 2y-3 is not equals y plus 2 AND how old are u?

This means that 2y - 3 = 2y + 4 which is not possible.

x = 1 and y = 6 so the lines intersect at the point (1, 6)

2y+26 = 28 2y = 28-26 2y = 2 y = 1

x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?

If you mean: x+7y = 39 and 3x-2y = 2 Then by substitution: x = 4 and y = 5

x + 2y = x + 2y Y and X aren't compatibles.

4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2

3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8

Both of them are equations! The solution is (x, y) = (2, 1).

The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).

The ordered pair is (6, 3).

4y + 4 = 2y + 12 Subtract 2y from each side of the equation: 2y + 4 = 12 Subtract 4 from each side: 2y = 8 Divide each side by 2: y = 4

-3x + 2y = 9 2y = 3x + 9 y = 1,5x + 4,5

The ordered pair is (3, 2).

The ordered pair is (2, 3).

The equation is -2y + 16 = 10

x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5

Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3

The solutions are: x = -2 and y = 4

If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5

x+2y = 7 2y = -x+7 y = -0.5x+3.5

2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6

If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5

If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7

4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4

2y + 3x = 0 2y + -3 = 0 2y = 0 + 3 , 2y = 3 y = 3/2 y = 1.5 x = -1

2y = 4x + 4 y = 2x + 2

3x + 2y = 8 This is an equation. It could be the equation of a line.

3x+2y=6 2y=-3x+6 y=-1.5x+3

5y = 2y+9 5y-2y = 9 3y = 9 y = 3

3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped

Subtract first from second gives -4x = 16 so x = -4 and y = -7

2y-7 = 14y+29 2y = 14y + 36 -12y = 36 -y = 3 y = -3

you can not solve this equation

They are parallel lines.

They are straight lines.

6y=5y+2y 6y=7y that does't work its unequal -

The standard form is 7x + 2y - 3 = 0

If: 2Y+3 = 11 then the value of Y is 4

x + 52 + 2y + 35 = 3 x + 2y = 3 - 52 -35 x + 2y = -84 Infinite number of solutions, are you sure you posted the correct equation?

5y-2y= 3y+2 5y-2y-3y= 2 0y= 2

2y + 4 = 3y Subtract 2y from both sides: 4 = y whew

4x+2y = 20 2y = -4x+20 y = -2x+10

4x+2y=24 => 2y=24-4x => y=12-2x and the slope is -2

3x = 2y + 7 The standard form is: 3x - 2y - 7 = 0

These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the ordered pair is - not are : (0.5, -1)

Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7