2x + 5y = 16 + (-5x) - 2y = 2
That gives 2x + 5y = 2 . . . . . . . . . . (I)
and
-5x - 2y = - 14 or 5x + 2y = 14 . . . . (II)
(I)*5: 10x + 25y = 10
(II)*2: 10x + 4y = 28
Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7
and then by (I)
x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7
So the ordered pair is (22/7, -6/7)
y=(-1) x=(2)
Your question does not make sense. It would probably be interpreted as a + = ++a ---a
x = 2 and y =-3 so the lines intersect at (2, -3)
-7
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. As far as one can tell the above expression looks like an equation for a line. If it is then it cannot be expressed as an ordered pair but requires an infinite number of ordered pairs!
The ordered pair is (1, 3).
16
The ordered pair is (1, 1).
(0, 6)
The solutions are: x = -2 and y = 4
(5,7)
(5,3)
The ordered pair is (5, 4).
The ordered pair is (-1, -2).
The ordered pair is (-1, -7).
No real roots.
There are an infinite number of ordered pairs. (-5, -7) is one pair