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moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml = 0.25 L

molarity = moles/liter = 1.34 moles/0.25 L = 5.37 M

Since KCl dissociates completely into K+ and Cl-, you have 5.37 M of each = total of 10.74 osmolar

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Q: What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?
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