Since you do not tell us the context of this scenario, we have no way of knowing.
input force x input distance > output force x output distance -Novanet
Mechanical advantage of an inclined plane: Ratio of force overcome by nature of weight of mass ( mass * acceleration due to gravity) to force required to move it. Example: ( take g as 10 (m/s)/s ) A mass of 10 kg is on a 30 degree incline , which generates (10 * 10) 100 newtons vertically down, the vector of this parallel to and down the slope is 100 * sin 30 degrees = 100 * 0.5 = 50 newtons which is the force required by the input force, so the ratio = 100:50 = 2:1 which is the mechanical advantage. This is also the ratio of vertical distance travelled by load : distance travelled up the slope
the equation of mechanical advantage isFout (force, output)divided byFin (force input)the equation for Ideal mechanical advantage isDin (distance, input)divided byDout (distance, output)hope this helps a bit
The answer is 5. To find mechanical advantage, divide the force required by the force given. 200/40 = 5
Also 100 newtons. Actually, that would only hold it in place - to push it back, you would need slightly more than 100 newtons.
If the machine were ideal ( 100% effiency) the output force would be 300 N In practice you might get 250 - 270.
a machine applies a force of 100 newtons over a distance of 10 meters to raise a500 newtons drum 1.5 meters. what is efficiency of the machine ?
The system is 100% efficient. Step 1: Find out Mechanical Advantage so that you can find out input force MA = input distance/output distance = 2.5m / 4.5 m = 0.5555555 Step 2: Find input force AMA = output force / input force 0.5555555 = 250 N / input force input force = 250 N/ 0.5555555 input force = 450 N Step 3: Solve for mechanical efficiency ME = ((output force x output distance) / (input force x input distance)) x 100% = ((250 N x 4.5 m) / (450 N x 2.5 m)) x 100% = (1125 Nm / 1125 Nm) x 100% = 1 x 100% = 100% *** MA = Mechanical Advantage *** AMA = Actual Mechanical Advantage *** ME = Mechanical Efficiency
input force x input distance > output force x output distance -Novanet
Mechanical advantage of an inclined plane: Ratio of force overcome by nature of weight of mass ( mass * acceleration due to gravity) to force required to move it. Example: ( take g as 10 (m/s)/s ) A mass of 10 kg is on a 30 degree incline , which generates (10 * 10) 100 newtons vertically down, the vector of this parallel to and down the slope is 100 * sin 30 degrees = 100 * 0.5 = 50 newtons which is the force required by the input force, so the ratio = 100:50 = 2:1 which is the mechanical advantage. This is also the ratio of vertical distance travelled by load : distance travelled up the slope
100 N due to newton's third law that every action has an opposite and equal reaction.
mechanical advantage= output force over input force times 100
the equation of mechanical advantage isFout (force, output)divided byFin (force input)the equation for Ideal mechanical advantage isDin (distance, input)divided byDout (distance, output)hope this helps a bit
distance over which the force is applied ________________________________ Distance over which the load was moved or MA= Effort Force _________ Load force OR MA= Length of Load arm ____________________X Weight/mass Length of Effort arm
The answer is 5. To find mechanical advantage, divide the force required by the force given. 200/40 = 5
That's going to depend on -- the radius from the center to the point where the input force is applied, -- the angle in the plane of the wheel between the direction of the force and the radius to it, and -- the radius from the center to the point where the output force is measured. None of that information is included in the question, so nobody is in a position to speculate on an answer yet.
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.