-3
The oxidation number of carbon in C2H4 is -3. This is because each hydrogen atom has an oxidation number of +1, and the overall molecule has a net charge of 0. The sum of the oxidation numbers in a neutral compound must equal zero.
Oxidation number is usually defined along the lines of the charge on the central atom if all "ligands" are removed along with the electron pairs.Now C2H4 is H2C=CH2 so we remove H as H- and leave a "charge" on the carbon atoms of 2+. the oxidation number of carbon is therefore (+)2.There is always debate about this term and the closely related term oxidation state. Confusingly some people use the term oxidation number to mean oxidation state.To calculate oxidation state which uses the relative electronegativity to determine which atom "keeps" the electrons, the hydrogens would be treated not as H- but as H+ leaving the carbon in an oxidation state of -2.My advice would be to check your notes and see which definition your teacher is using.
The oxidation number of carbon in ethene (C2H4) is +2. In this molecule, each carbon atom forms two single bonds with hydrogen atoms, resulting in a total of four electrons being shared with hydrogen. The remaining four electrons are equally shared between the two carbon atoms, resulting in an oxidation state of +2 for each carbon atom.
The oxidation number of carbon in K2CO3 is +4. This is because the oxidation number of potassium (K) is +1 and the oxidation number of oxygen (O) is -2, which allows for the calculation of carbon's oxidation number.
The oxidation number for carbon in CHI3 compound is -2. In CHI3, iodine has an oxidation number of -1 and hydrogen has an oxidation number of +1, which allows carbon to have an oxidation number of -2 to balance the overall charge of the compound.
The oxidation number of carbon in C2H4 is -3. This is because each hydrogen atom has an oxidation number of +1, and the overall molecule has a net charge of 0. The sum of the oxidation numbers in a neutral compound must equal zero.
Oxidation number is usually defined along the lines of the charge on the central atom if all "ligands" are removed along with the electron pairs.Now C2H4 is H2C=CH2 so we remove H as H- and leave a "charge" on the carbon atoms of 2+. the oxidation number of carbon is therefore (+)2.There is always debate about this term and the closely related term oxidation state. Confusingly some people use the term oxidation number to mean oxidation state.To calculate oxidation state which uses the relative electronegativity to determine which atom "keeps" the electrons, the hydrogens would be treated not as H- but as H+ leaving the carbon in an oxidation state of -2.My advice would be to check your notes and see which definition your teacher is using.
The oxidation number of carbon in ethene (C2H4) is +2. In this molecule, each carbon atom forms two single bonds with hydrogen atoms, resulting in a total of four electrons being shared with hydrogen. The remaining four electrons are equally shared between the two carbon atoms, resulting in an oxidation state of +2 for each carbon atom.
The oxidation number of carbon in K2CO3 is +4. This is because the oxidation number of potassium (K) is +1 and the oxidation number of oxygen (O) is -2, which allows for the calculation of carbon's oxidation number.
The oxidation number for carbon in CHI3 compound is -2. In CHI3, iodine has an oxidation number of -1 and hydrogen has an oxidation number of +1, which allows carbon to have an oxidation number of -2 to balance the overall charge of the compound.
The oxidation number for carbon in C2H6O is -3. This is calculated by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then applying algebra to determine the oxidation number of carbon.
The oxidation number of carbon in formaldehyde (HCHO) is +2. In this molecule, oxygen has an oxidation number of -2, and hydrogen has an oxidation number of +1. By applying the rules for assigning oxidation numbers in a compound, we can determine that carbon has an oxidation number of +2.
The oxidation number of carbon in CH3OH is -2. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2. By assigning these values to the other atoms in the molecule, we can determine that carbon must have an oxidation number of -2 to balance the overall charge of the molecule.
H is +1, O is -2 overall carbon will have an oxidation # of -3
The oxidation number of carbon in CO is +2. This is because the oxidation number of oxygen is typically -2, and there is only one oxygen atom in CO, so the oxidation number of carbon must be +2 to balance the charge.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Hydronium ion is H3O+ ion and has no carbon in it.