its 0 you jackass!
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
Carbon has +2 oxidation number in Carbon monoxide. It gets this oxidation number when it loses or shares two electrons.
The oxidation state of carbon in CH3OH is 4
In the hydronium ion (H3O+), the oxidation number of carbon is +3.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
Carbon has +2 oxidation number in Carbon monoxide. It gets this oxidation number when it loses or shares two electrons.
The oxidation state of carbon in CH3OH is 4
In the hydronium ion (H3O+), the oxidation number of carbon is +3.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.
I believe K2CO3.
The oxidation number is + for C and -2 for O.
the answer is 0.
Carbon is in the 14th group. Carbon normally shows +4 oxidation number.
+4 for carbon
The oxidation number of H is +1 and the oxidation numbers of each carbon are +3
Nitrogen's oxidation number is -4.Carbon's oxidation number is +3.The cyanide ion has -1 charge. Nitrogen is in -3 state. By balancing the charges: the oxidation number of carbon is +4.