If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero.
If the question is Cu2+, then the oxidation number is +2.
Elemental copper (Cu) is in oxidation state '0'.
The copper cation can exhibit two oxidation states, they are +1 & +2
In oxidation state +1 it forms cuprous sulphide ( Cu2S)
In oxidation state +2 it form cupric sulphide (CuS)
NB THere are other compounds of copper exhibiting these oxidation states.
Copper is one of the transition metals that have two different oxidation numbers. For copper, it can either be Couprous, which has an oxidation number of +1. The other possibility is coupric, which has an oxidation number of +2.
0 in elemental form
+1 or +2 in its compounds
0 in the elemental form, +1 or +2 in its compounds.
The oxidation number of Cu as a reactant is zero (before a reaction).
Cu = +1
Cu is +2 and F is -1
Oxidation number is the charge per atom in a compound. Cl2= 2- (Cl= 1-) Cu would have to be 2+ to balance the compound, because there is only one copper atom.
+2 for Cu, +4 for C, -2 for O
cu =1+ fe=3+ s=2-
Cu = +1
The oxidation of any element, by itself, is zero.
The oxidation number tells you the "combining power" of that element. For example, if Cu has a 1+ oxidation number then it will combine with Cl in a 1:1 ratio, and result in CuCl. If Cu has an oxidation number of 2+, then it will combine with Cl in a 1:2 ratio, and result in CuCl2.
Cu is +2 and F is -1
Oxidation number is the charge per atom in a compound. Cl2= 2- (Cl= 1-) Cu would have to be 2+ to balance the compound, because there is only one copper atom.
+2 for Cu, +4 for C, -2 for O
cu =1+ fe=3+ s=2-
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
Cu
+1 for Cu, +1 for H, +6 for S, -2 for each O
Cu ----> Cu 2+ + 2e-
Cl2 + 2Cu --> 2CuCl Oxidation reaction is Cu --> Cu+ + 1e Reduction reaction is Cl + 1e --> Cl- Redox reaction is Cu + Cl --> Cu+ + Cl-