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What is the ionic compound name Na2 So4?
This is sodium sulphate.
What is the oxidation number of (nh4)2ce(so4)3?
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
What is the oxidation number of Cr in Cr2(SO4)3?
The oxidation number of chromium (Cr) in Cr2(SO4)3 is +3. This is because the overall charge of the sulfate ion (SO4) is -2, and there are a total of 3 sulfate ions present in the compound, requiring the chromium to have an oxidation state of +3 to balance the charges.
What is the oxidation number for s in tin IV sulfate?
The oxidation number for sulfur (S) in tin(IV) sulfate (Sn(SO4)2) is +6. This is because the overall charge of the sulfate ion (SO4) is -2, and there are two sulfate ions present in the compound, leading to a total charge of -4. The oxidation number of tin (Sn) in this compound is +4.
What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the ionic compound name Na2 So4?
This is sodium sulphate.
What is the oxidation number of (nh4)2ce(so4)3?
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
What is the oxidation number of Cr in Cr2(SO4)3?
The oxidation number of chromium (Cr) in Cr2(SO4)3 is +3. This is because the overall charge of the sulfate ion (SO4) is -2, and there are a total of 3 sulfate ions present in the compound, requiring the chromium to have an oxidation state of +3 to balance the charges.
What is the oxidation number for s in tin IV sulfate?
The oxidation number for sulfur (S) in tin(IV) sulfate (Sn(SO4)2) is +6. This is because the overall charge of the sulfate ion (SO4) is -2, and there are two sulfate ions present in the compound, leading to a total charge of -4. The oxidation number of tin (Sn) in this compound is +4.
What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the oxidation numbers for SO4?
This should be SO4-2 ion. sulfur shows +6 in this ion.
What is Oxidation numbers for SO4?
This should be SO4-2 ion. sulfur shows +6 in this ion.
What is the oxidation number of SO4?
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
What does na2 so4 mean?
Na2SO4 is the chemical formula for sodium sulfate, which is a compound formed by the combination of sodium ions (Na+) and sulfate ions (SO4^2-). It is a white, crystalline solid that is commonly used in the manufacturing of glass, paper, and detergents.
WHAT IS THE OXIDATION NUMBER OF AL2(SO4)3?
The oxidation number of Al in Al2(SO4)3 is +3 because each sulfate ion (SO4) has a charge of -2 and there are 3 sulfate ions, leading to a total charge of -6. In order for the compound to be neutral, the aluminum ions must have a total charge of +6, leading to an oxidation number of +3 for each aluminum ion.
What is the oxidation number of O in SO4?
Oxygen atoms are generally considered to have an oxidation number of -2 in all oxyanions such as sulfate.
What is the oxidation number of PbSO4?
The oxidation number of Pb in PbSO4 is +2. This is because the oxidation number of oxygen is typically -2, and the overall charge of the sulfate ion (SO4) is -2, so the oxidation number of Pb must be +2 to balance the charges in the compound.
