The oxidation number of carbon in glucose is +4. This is because in glucose (C6H12O6), each oxygen atom has an oxidation number of -2 and each hydrogen atom has an oxidation number of +1, so the carbon atoms must have an oxidation number of +4 in order to balance the overall charge of the molecule.
The oxidation number of carbon (C) in glucose is +4. This is because in glucose (C6H12O6), each carbon atom is bonded to one oxygen atom, and oxygen is more electronegative than carbon, resulting in a higher oxidation state for carbon.
In glucose (C6H12O6), the oxidation number of carbon is +4 or -4, oxygen is -2, and hydrogen is +1. The overall charge of the molecule is neutral.
Beans
The oxidation number of carbon in K2CO3 is +4. This is because the oxidation number of potassium (K) is +1 and the oxidation number of oxygen (O) is -2, which allows for the calculation of carbon's oxidation number.
The oxidation number for carbon in CHI3 compound is -2. In CHI3, iodine has an oxidation number of -1 and hydrogen has an oxidation number of +1, which allows carbon to have an oxidation number of -2 to balance the overall charge of the compound.
The oxidation number of carbon (C) in glucose is +4. This is because in glucose (C6H12O6), each carbon atom is bonded to one oxygen atom, and oxygen is more electronegative than carbon, resulting in a higher oxidation state for carbon.
In glucose (C6H12O6), the oxidation number of carbon is +4 or -4, oxygen is -2, and hydrogen is +1. The overall charge of the molecule is neutral.
Beans
The oxidation number of carbon in K2CO3 is +4. This is because the oxidation number of potassium (K) is +1 and the oxidation number of oxygen (O) is -2, which allows for the calculation of carbon's oxidation number.
The oxidation number for carbon in CHI3 compound is -2. In CHI3, iodine has an oxidation number of -1 and hydrogen has an oxidation number of +1, which allows carbon to have an oxidation number of -2 to balance the overall charge of the compound.
The oxidation number for carbon in C2H6O is -3. This is calculated by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then applying algebra to determine the oxidation number of carbon.
The oxidation number of carbon in formaldehyde (HCHO) is +2. In this molecule, oxygen has an oxidation number of -2, and hydrogen has an oxidation number of +1. By applying the rules for assigning oxidation numbers in a compound, we can determine that carbon has an oxidation number of +2.
The oxidation number of carbon in CH3OH is -2. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2. By assigning these values to the other atoms in the molecule, we can determine that carbon must have an oxidation number of -2 to balance the overall charge of the molecule.
H is +1, O is -2 overall carbon will have an oxidation # of -3
The oxidation number of carbon in CO is +2. This is because the oxidation number of oxygen is typically -2, and there is only one oxygen atom in CO, so the oxidation number of carbon must be +2 to balance the charge.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Hydronium ion is H3O+ ion and has no carbon in it.