1-
The oxidation number of H in NaHSO4 is +1. In this compound, Na has an oxidation state of +1, S has an oxidation state of +6, and O has an oxidation state of -2. By adding up the oxidation states and solving for H, it is determined to be +1.
In the reaction Mg + HO → Mg + H, the oxidation state of each hydrogen atom in H (which is diatomic hydrogen, H₂) is 0. This is because in its elemental form, hydrogen exists as H₂, and elements in their natural state have an oxidation state of zero.
The oxidation state (or number) is zero. This is true for any element in any of its allotropic elemental forms.
N has +3 state on it.Each H have -1 state.
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
zero- H2 is the elemental form- by definition the ON# is zero
In LiH, the oxidation number of Li is +1 and the oxidation number of H is -1. This is because lithium typically has a +1 oxidation state and hydrogen typically has a -1 oxidation state in ionic compounds.
The oxidation state of Cl in HClO3 is +5. This is because the sum of the oxidation states in a neutral molecule must be zero, and since H has an oxidation state of +1, O has an oxidation state of -2, the oxidation state of Cl must be +5 in order to balance the charges.
The oxidation state of Cl in HClO4 is +7. In HClO4, since the oxidation state of H is +1 and that of O is -2, the sum of the oxidation states in the compound must equal 0. Therefore, the oxidation state of Cl in this case is +7.
O = -2 oxidation state H = +1 oxidation state
The oxidation number of hydrogen (H) in HBr is +1. In binary ionic compounds, such as HBr, hydrogen typically has an oxidation state of +1.
HIO4.2H2O O.S. of H = +1 O.S. of I = +7 O.S. of O = -2