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What is the pH of 535 ml of gaseous HCL at 26.5 degree C and 747 mmHg is dissolved in enough water to prepare 625ml solution?
Wiki User
∙ 13y ago
Let's try this.
PV = nRT
( 26.5 C = 299.65 K )(535 ml = 0.535 Liters )
(747 mmHg)(0.535 Liters) = (n)(62.36 L*torr/mol*K)(299.65 K )
= 0.021387 moles HCl(g)
now....
Molarity = moles solute/Liters of solution (625 ml = 0.625 Liters
Molarity HCl(g) = 0.021387 moles/0.625 Liters
= 3.422 X 10^-2 M
-log(3.422 X 10^-2 M)
= 1.4657 pH
final answer ( trim to significant figures )
Wiki User
∙ 13y ago
Esther Osei Ampomah
Wiki User
∙ 8y ago1.5g calcium hydroxide = 0.02mol, and M=0.02mol/0.765L=0.026M. [OH-]=2(0.026)=0.052. pOH=-log(0.052)=1.28. 14-1.28=12.72, and that's your pH. You would expect a basic reading, because calcium hydroxide is a strong base in solution.
Wiki User
∙ 16y ago- log ((1.5 / 36.5) * 0.35) = 1.8
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