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What is the pH of 6.8 x 10 -3 M?

Updated: 9/26/2023
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6y ago

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It depends on what compound is dissolved in what solvent.

Presuming a strong monoprotic acid (eg. HCl) in water the pH is equal to -log[H+] = -log(6.8*10^-3) = 3-log6.8 = (3-0.8) = 2.2

Presuming a strong monoprotic base (eg. NaOH) in water the pH is equal to 14 - pOH = 14 - (-log[OH-]) = 14+log(OH-) = 14 + log(6.8*10^-3) = 14 + (-3 + log6.8) = 14 + (-3+0.8) = 14 - 2.2 = 11.8

Fot pH calculation of weak acids and bases you'll need more complex formula and approximations.

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Q: What is the pH of 6.8 x 10 -3 M?
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