5.0 x 10-3 pH = - log [H3O+] [H3O+] = 1 x 10^-pH pH = 2.3 [H3O+] = 1 x 10^(-2.3) = 5 x 10^(-3) M
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
The pH of a solution can be calculated using the formula pH = -log[H+]. Substituting the given value of [H+] = 7.0 x 10^-12 into the formula gives pH = -log(7.0 x 10^-12) ≈ 11.2. Therefore, the pH of the solution is approximately 11.2.
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
The pH of a solution with a H+ concentration of 7.0 x 10^-2 M can be calculated using the formula pH = -log[H+]. In this case, pH = -log(7.0 x 10^-2) = 1.15.
1.70
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
2
1.15 (Apex)
-log(9.40 X 10^-4) = 3 pH
apexvs answer 3.3
The pH of a solution can be calculated using the formula pH = -log[H+]. Substituting the given value of [H+] = 7.0 x 10^-12 into the formula gives pH = -log(7.0 x 10^-12) ≈ 11.2. Therefore, the pH of the solution is approximately 11.2.
In a neutral solution, the H plus is equal to OH-. The pH level in such a solution is usually at 7.
The pH of a solution is calculated using the formula pH = -log[H+]. Plugging in the given value of [H+] = 7.0x10^-7, you would get a pH of 6.15 for this solution.
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
The pH of a solution with a H+ concentration of 7.0 x 10^-2 M can be calculated using the formula pH = -log[H+]. In this case, pH = -log(7.0 x 10^-2) = 1.15.