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5.0 x 10-3 pH = - log [H3O+] [H3O+] = 1 x 10^-pH pH = 2.3 [H3O+] = 1 x 10^(-2.3) = 5 x 10^(-3) M

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The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.


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The pH of a solution can be calculated using the formula pH = -log[H+]. Substituting the given value of [H+] = 7.0 x 10^-12 into the formula gives pH = -log(7.0 x 10^-12) ≈ 11.2. Therefore, the pH of the solution is approximately 11.2.


In neutral solution the H plus is?

In a neutral solution, the H plus is equal to OH-. The pH level in such a solution is usually at 7.


What is the pH of a solution with H plus equals 7.0 10-7?

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What is the pH of a solution with H plus equals 7.0 10-2?

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