Since no2 in liquid form is considered an acid, it has a ph lower than 7 yet it is still consumable therefor it is a weak acid most likely with a ph of higher than 4
NO2 is more harmful to the environment than NO2-.
HNO2 ==> H+ + NO2^-Ka = 4x10^-4 = [H+][NO2^-]/[HNO2] 4x10^-4 = (x)(x)/0.100 x^2 = 4x10^-5 x = 6.32x10^-3 = [H+] pH = -log 6.32x10^-3 pH = 2.2
The conjugate base of HNO2 is NO2-. When HNO2 loses a proton, it forms its conjugate base, nitrite ion (NO2-).
NO2 plus (NO2+) is a cationic species with a positive charge, while NO2 is a neutral molecule. NO2 is a brown gas at room temperature, whereas NO2+ is a highly reactive and unstable species that is rarely encountered independently.
The name of NO2- is nitrite.
NaNO2 yields NO2 - + Na+ The salt NaNO2 completely ionizes, producing 0.35M [NO2-] and 0.35 [Na+] ions. NO2- is the conjegate base of the weak acid HNO2. You have to write a balanced equation for the reation at equilibrium. After you have done so, you need to set up an ICE (Initial, change, equilibrium) table, experssing the equilibrium concentrations of all species in terms of initial concentrations and a single unknown x, that represenst the change in concentraion: NO2 - + H2O yields HNO2 + OH- ---- Initial 0.35 0.00 0.00 Change -x +x +x ---- Equil. 0.35-x x x Know we use the equilibrium equation: Kb = [HNO2][OH-]/[NO2 - ] (2.5 x 10-11) = x2/ 0.35 - x (in this case we can omitt the x that is subtracted from the 0.35 concentration because the Kb value is so small and will not affect the value) So, 2.5 x 10-11 = x2/0.35 x = [OH-] = 2.96 x 10-6 Now that we have solved for the OH- concentration, we can solve for the pOH and then use that to solve for the pH. pOH = -log[OH-] pOH = -log[2.96 x 10-6] pOH = 5.53 pH + pOH = 14 pH = 14 - pOH pH= 14 - 5.53 pH= 8.47 ----
These are oxides which can form acids: NO2, SO2, CO2.
NO2 is more harmful to the environment than NO2-.
NO2 is the molecular formula for NO2.
When ammonium nitrite (NH4NO2) dissolves in water, it forms nitrite (NO2-) ions and ammonium (NH4+) ions, which can be slightly acidic due to the release of hydrogen ions (H+). On the other hand, nitrate (NO3-) ions from ammonium nitrate (NH4NO3) do not have a significant impact on water pH as they are neutral. Overall, the net effect on water pH will depend on the relative amounts and concentrations of these ions present.
HNO2 ==> H+ + NO2^-Ka = 4x10^-4 = [H+][NO2^-]/[HNO2] 4x10^-4 = (x)(x)/0.100 x^2 = 4x10^-5 x = 6.32x10^-3 = [H+] pH = -log 6.32x10^-3 pH = 2.2
No. NO2 Is Nitrogen Dioxide.
The conjugate base of HNO2 is NO2-. When HNO2 loses a proton, it forms its conjugate base, nitrite ion (NO2-).
NO2 plus (NO2+) is a cationic species with a positive charge, while NO2 is a neutral molecule. NO2 is a brown gas at room temperature, whereas NO2+ is a highly reactive and unstable species that is rarely encountered independently.
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
Yes, because water absorb from atmosphere gases wit acidic potential (CO2, NO2, SO2, etc.) and become more acidic.
NO2 is the chemical formula for nitrous oxide.