Want this question answered?
pH 8: [H+] = 10^-8 M pH 6: [H+] = 10^-6 M 10^-6 / 10^-8 = 10^2 = 100 Answer is 100 times fewer
pH 8: [H+] = 10^-8 M pH 6: [H+] = 10^-6 M 10^-6 / 10^-8 = 10^2 = 100 Answer is 100 times fewer
1.70
5.64
pH = -log[H+] = -log(3.7 x 10-6) = 5.43
5.7
pH 8: [H+] = 10^-8 M pH 6: [H+] = 10^-6 M 10^-6 / 10^-8 = 10^2 = 100 Answer is 100 times fewer
pH 8: [H+] = 10^-8 M pH 6: [H+] = 10^-6 M 10^-6 / 10^-8 = 10^2 = 100 Answer is 100 times fewer
No, a pH of 5 is ten times more acidic than a pH o6.
From pH=2 to pH=6 the factor 1is 10 000. The factor is 10 for one unit of pH.
Looks as if you will need to calculate the pH of the final solution. The formula you need will be [H+] = 1 x 10-6 M.
1.70
At 'half way' point the pH is equal to the pKa value of the acid: pH = pKa - log[cA/cB] because at that point cA = cB . So pH = pKa = - log(5.2*10-6) = 5.3
5.64
pH = -log[H+] = -log(3.7 x 10-6) = 5.43
A solution of HCl is highly dissociated into ions, A 0.000001 M solution (1 x 10-6) has a pH of 6 ... close to neutral. A 0.001 M solution (1 x 10-3) has a pH of 3 ... more concenterated, but still not a really concentrated solution. A 0.1 M solution (1 x 10-1) has a pH of 1 ... even more concentrated. showing it is more acidic.
pH 6 is a very weak acid and pH 9 is an alkaline