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What is the pH of pure water at 313 K if Kw at that temperature is 2.917 x 10 -14?
Wiki User
∙ 11y ago
Kw = [H+][OH-] [H+] = 10-pH = 10-6.17 For [OH-] remember that heat causes more water molecules to self-dissociate but for every new H+ generated, a OH- is generated as well. Therefore, the concentration of H+ and OH- is equal. [OH-] = 10-6.17 Kw = [H+][OH-] = 10-6.17 * 10-6.17 = 10-12.34
Wiki User
∙ 15y ago
Wiki User
∙ 11y ago"The pH of PURE water will always be 7."
This is false. As the temperature rises for pure water, so does the Kw value. Kw=2.917 x 10^-14.
Kw=[OH-][H+].
Kw=[1.708 x 10^-7]^2.
-log(1.708 x 10^-7)=6.76=pH
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