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What is the temperature of 25.0 g of chlorine gas with a volume of 6.0 Liters and a pressure of 1.5 ATM?
Wiki User
∙ 8y ago
Moles Cl2 = 25g x 1mol/71g 0.35 molesPV =nRT and T = PV/nR
T = (1.5)(6)/(0.35)(.0821)
T = 313 deg K = 40.2 deg C to 3 sig figs
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoThe temperature is 155,6 K.
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When the pressure of a gas increases at constant temperature its volume?
Temperature increases as pressure increases.
According to the volume of a gas increases with increasing temperature provided the pressure does not change?
Since you have more molecules, then you are trying to pack more molecules into the same space (volume). Since more molecules are in the same space, then more molecules will be hitting the wall of the container (same volume). Since more are hitting the container wall , then the pressure increases.
What will happen to gas pressure when the volume is decreased?
When the temperature of a gas is increased at a constant pressure, its volume increases. When the temperature of a gas is devreased at constnt pressure, its volume decreases.
Volume temperature pressure?
P1V1=P2V2 P1V1/T1=P2V2/T2 PV=nRT P=pressure V=volume n=number of moles R=the gas constant 8.31J/molK or 0.0821Latm/molK T=temperature in kelvin
When A balloon has a volume of 10500 liters and the temperature is 15 and degC. If the temperature were -25 and degC what would the volume of the balloon be?
It would be approx 9042 litres.
What volume is occupied of 2.4 moles of chlorine?
54 liters at STP (standard temperature and pressure)
What is the volume occupied by 0.25 mol of chlorine gas?
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
What is the volume of 0.8 moles of chlorine gas at Standard Temperature and Pressure?
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
What volume is contained of 2.4 moles of chlorine and how do you work it out?
I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation. PV = nRT (1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K) Volume = 59 Liters of chlorine gas --------------------------------------------
What determines the volume of gas?
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.
What determines a gas's of volume?
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.
What is the mass of 100 ml of chlorine in grams?
The mass of the Chlorine will depend upon the density of the Chlorine which depends upon the temperature and pressure of the Chlorine. Assuming stp (standard temperature and pressure) the density of Chlorine is 0.0032 g/ml. density = mass / volume → mass = volume × density = 100 ml × 0.0032 g/ml = 0.32 g.
What is chlorine's density in grams per milliliter or g mL?
Chlorine is a gas. Its density depends on pressure, temperature and volume of the container.
How does the volume of a gas vary?
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.
What volume is occupied of 0.48 moles of hydrogen?
0.48 liters at STP (standard temperature and pressure)
A balloon is filled with helium. Its volume is 4.2L at 312.K. What will its volume in liters be at 285.K assuming no change in pressure?
Assuming pressure is constant, like you said, volume and temperature have a direct relationship. As temperature increases, volume increases; as temperature decreases, volume decreases. Setting up a algebraic direct proportion, you get approximately 3.84 liters for the balloon at 285 degrees K.
The volume of the balloon is 3 liters at a temperature of 300 degrees kelvin What will the volume of the balloon be if the temperature rises to 350?
3.5 litre if pressure is kept constant.
