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I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation.

PV = nRT

(1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K)

Volume = 59 Liters of chlorine gas

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Q: What volume is contained of 2.4 moles of chlorine and how do you work it out?
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