Approx 26.8%
Approx 32.8%.
Sodium oxide contain 25,8 % oxygen.
Calculate the mass of Oxygen in the tin oxide
50
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
Approx 32.8%.
Sodium oxide contain 25,8 % oxygen.
Calculate the mass of Oxygen in the tin oxide
2. beryllium oxide. Each oxide contains as many oxygen atoms as alkaline earth metal atoms, and beryllium has the smallest atomic weight of the alkaline earth metals. Therefore, beryllium oxygen has the greatest percentage by weight of oxygen.
The percent by mass of oxygen in N2O4 is 69,56 %.
If 20g of mercury oxide were heated, the combined mass of oxygen and mercury would be 20 grams.
In higher oxide Metal = 80% Oxygen = (100-80)% = 20% Therefore, we can say that 4 parts of metal combines with 1 part of oxygen. Now, 0.72 g of lower oxide on oxidation gives 0.8 g of higher oxide. It can be assumed that the mass percent of metal in 0.8 g is same as that of 0.72 g of lower oxide. So, Mass of metal in higher oxide = (80/100) x 0.8 g = 0.64 g If in 0.8 g of higher oxide 0.64 g is metal then mass of oxygen present in higher oxide will be (0.8 - 0.64) g = 0.16 g Since, lower oxide contains the same mass of metal as that of higher oxide, we need to calculate the mass of oxygen in lower oxide. Mass of oxygen in lower oxide = (0.72-0.64) g = 0.08 g According to Law to multiple proportions if two elements combine with each other to form two different compounds then the ratio of masses of that element which combines with the other element whose mass is fixed in both the compounds, will be in small whole numbers. Now, in the given problem the mass of metal in both the oxide is fixed so, for the data to illustrate the law of multiple proportion the ratio of mass of oxygen in both the oxides should be in whole numbers. Now, mass of oxygen in higher oxide : mass of oxygen in lower oxide = 0.16 : 0.08 = 2 : 1. Therefore, it can be said that the given data depicts law of multiple proportion.
The answer is 2,871 g oxygen.
The oxide N2O3 has a lower percent of mass nitrogen.
50
The answer is 1,425 g oxygen.
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.