If it's a 12 by 5 rectangle then the perimeter is: 12+5+12+5 = 34 cm
34cm
If two sides of a triangle have lengths of 5cm and 12cm, then the third side can have any length that's more than 7cm and less than 17cm. If the third side is 13cm, then the triangle is a right triangle.
4 x 5cm = 20cm
The circumference of a circle with a radius of 5cm is: 31.42 cm
16 cm 5cm+5cm+3cm+3cm=16cm
34cm
The area of a 12cm by 5cm right-angled triangle is: 42 cm2
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm
30 square cm because it's a right angle triangle
2.4
this is 5cm (:
5cm 2cm
the perimeter of a rectangle with two 5cm squares will be 30cm
9cm + 5cm + 9cm + 5cm = 28cm
30cm
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
I cut out the lengths to have a visual look at the problem and the answer is NO you cannot arrange 5cm, 12cm, and 19cm into a triangle. Even straightening out the lengths of 5cm and 12cm into a 180 degree angle will not measure out to the 19cm. You cannot have a side that is more than the length of the other two sides combined in a triangle.