Since there are two of each side, there are two 9s and two 12s, so the perimiter is 2*12+2*9, which is 24+18, which is 42.
A rectangle with sides of 1cm and 6cm has an area of 6 cm2 and a perimeter of 14 cm. A rectangle with sides of 2cm and 3cm has the same area but its perimeter is 10 cm.
The rectangle has a length of 12 cm and a width of 3 cm.
It has 2 sides of 5 cm and 2 sides of 6 cm so the perimeter is 22 cm
If it's a 12 by 5 rectangle then the perimeter is: 12+5+12+5 = 34 cm
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
11 cm2 zero, when two opposite sides are 12 cm, and the rectangle is infinitely thin
Add up the lengts of all four sides.
The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.The perimeter of a 12 cm x 3 cm rectangle is 2*(12+3) cm = 2*15 cm = 30 cm.
The answer is 12 cm.
12 cm
A rectangle with sides of 1cm and 6cm has an area of 6 cm2 and a perimeter of 14 cm. A rectangle with sides of 2cm and 3cm has the same area but its perimeter is 10 cm.
100 cm
30 cm. 2 sides are 9 cm and 2 sides are 6 cm (2x9)+(2x6)=? 18+12=30
The perimeter is the sum of the four sides. In this case, two sides have 14 cm each, and the other two sides have 5 cm eacn.
The rectangle has a length of 12 cm and a width of 3 cm.
Write an equation for the perimeter, and solve it. Remember that the perimeter is the sum of all four sides.
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm