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Let the other diagonal be x:-

If area is: 0.5*x*7.5 = 37.5

Then x is: 37.5/(0.5*7.5) = 10

The rhombus will then have 4 right angles with sides of 5 and 3.75

Using Pythagoras: hypotenuse of each triangle is 6.25 cm

Therefore perimeter of the rhombus is: 4*6.25 = 25 cm

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Q: What is the perimeter of a rhombus when one of its diagonals is 7.5cm and has an area of 37.5 square cm?
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