A ziggurat could be oval, rectangular, square, or any other shape. If happened to have a square base, its perimeter would be four times its length (4 x 22 meters = 88 it meters).
4 x22m = 88m.
Perimeter of a rectangle = twice (length + width), in this case 22 m.
22 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (4) + 2 (7) = 22
length = 22 meters and width = 6 meters
22 meters.
Perimeter = 25 + 25 + 22 + 22 = 94
Multiply for the area, add for the perimeter.
22 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (8) + 2 (3) = 16 + 6 = 22 also: P = 2 (L + W) 2(8 + 3) = 22
22
2 x 8 metres plus 2 x 3 metres = a perimeter of 22 metres.
Width = X Length = 3X Four sides to the perimeter: x + x + 3x + 3x = 8x 8x = 22 x = 2.75 3x = 8.25 The length is 8.25.
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
22