The period is the time taken to complete one cycle. In this case it would be three seconds. The frequency of the swing is the inverse of the period. 1/3Hz
The period is the time for a full cycle, i.e., back and forth.
The period of a 0.85 meter long pendulum is 1.79 seconds.
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
A pendulum with a period of five seconds has a length of 6.21 meters.
For small amplitudes, the period can be calculated as 2 x pi x square root of (L / g). Convert the length to meters, and use 9.8 for gravity. The answer will be in seconds. About 1.4 seconds.
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
The period of a 0.85 meter long pendulum is 1.79 seconds.
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
For a simple pendulum: Period = 6.3437 (rounded) seconds
A pendulum with a period of five seconds has a length of 6.21 meters.
Approx 80.5 centimetres.
The period is 1 second.
5.94 m
2.01 seconds.
The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.
For small amplitudes, the period can be calculated as 2 x pi x square root of (L / g). Convert the length to meters, and use 9.8 for gravity. The answer will be in seconds. About 1.4 seconds.