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If the mass of bob of a simple pendulum is doubled its time period is what?
The time period of a simple pendulum is not affected by the mass of the bob, as long as the amplitude of the swing remains small. So, doubling the mass of the bob will not change the time period of the pendulum.
What is the period of a simple pendulum 80 cm long a on earth and b when it is in a freely falling elevator?
a) The period of a simple pendulum on Earth depends on the acceleration due to gravity, which is approximately 9.81 m/s^2. Using the formula for the period of a pendulum, T = 2pisqrt(L/g), where L is the length of the pendulum (80 cm = 0.8 m), we find T = 2pisqrt(0.8/9.81) ≈ 1.79 seconds. b) In a freely falling elevator, the acceleration due to gravity acts on both the elevator and the pendulum, so the period of the pendulum remains the same as on Earth, assuming no air resistance or other external factors.
How long must a simple pendulum be in order to have a period of one second?
A simple pendulum must be approximately 0.25 meters long to have a period of one second. This length is calculated using the formula for the period of a simple pendulum, which is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. By substituting T = 1 second and g = 9.81 m/s^2, you can solve for L.
Discussion of the measurement of gravity by a bar pendulum?
A bar pendulum is a simple pendulum with a rigid bar instead of a flexible string. Gravity can be measured using a bar pendulum by observing the period of oscillation, which relates to the acceleration due to gravity. By timing the pendulum's swing and applying the appropriate formulae, the value of gravity can be calculated. This method provides a simple and effective way to measure gravity in a laboratory setting.
A simple pendulum is 5.00 m long What is the period of simple harmonic motion for the pendulum if it is placed in a truck that is accelerating horizontally at 5.00ms2?
The period of a simple pendulum depends only on its length and acceleration due to gravity, and not on any horizontal acceleration. So, the period of the simple pendulum in the truck would be the same as if it were stationary, which can be calculated using the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity.
If the mass of bob of a simple pendulum is doubled its time period is what?
The time period of a simple pendulum is not affected by the mass of the bob, as long as the amplitude of the swing remains small. So, doubling the mass of the bob will not change the time period of the pendulum.
What is the period of a simple pendulum 80 cm long a on earth and b when it is in a freely falling elevator?
a) The period of a simple pendulum on Earth depends on the acceleration due to gravity, which is approximately 9.81 m/s^2. Using the formula for the period of a pendulum, T = 2pisqrt(L/g), where L is the length of the pendulum (80 cm = 0.8 m), we find T = 2pisqrt(0.8/9.81) ≈ 1.79 seconds. b) In a freely falling elevator, the acceleration due to gravity acts on both the elevator and the pendulum, so the period of the pendulum remains the same as on Earth, assuming no air resistance or other external factors.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
How long must a simple pendulum be in order to have a period of one second?
A simple pendulum must be approximately 0.25 meters long to have a period of one second. This length is calculated using the formula for the period of a simple pendulum, which is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. By substituting T = 1 second and g = 9.81 m/s^2, you can solve for L.
If the length of a simple pendulum is doubled what will be the change in its time period?
ts period will become sqrt(2) times as long.
The time period of a simple pendulum having infinite length will be?
It would tend towards infinity
Discussion of the measurement of gravity by a bar pendulum?
A bar pendulum is a simple pendulum with a rigid bar instead of a flexible string. Gravity can be measured using a bar pendulum by observing the period of oscillation, which relates to the acceleration due to gravity. By timing the pendulum's swing and applying the appropriate formulae, the value of gravity can be calculated. This method provides a simple and effective way to measure gravity in a laboratory setting.
A simple pendulum is 5.00 m long What is the period of simple harmonic motion for the pendulum if it is placed in a truck that is accelerating horizontally at 5.00ms2?
The period of a simple pendulum depends only on its length and acceleration due to gravity, and not on any horizontal acceleration. So, the period of the simple pendulum in the truck would be the same as if it were stationary, which can be calculated using the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity.
Value of g by simple pendulum?
You can build a simple pendulum - one that has most of its mass concentrated in a small place, at the end of the pendulum. Measure the pendulum's length, and measure how long it takes to go back and forth. Use the formula for the period of a pendulum, solving for "g".
What is the period of a simple pendulum 80 cm long on the earth and when it is in a freely falling elevator?
In a freely falling elevator, there would be a period of infinite length, because in freefall, the objects act as if there is no gravity. On earth, the period is given as the quantity 2pi times the square root of the quantity length/g. g is the gravitational constant, which is 9.8 on earth. The period of the pendulum does not depend on how far you pull it back, or how much mass is on the pendulum. Both are common misconceptions. I don't have access to a calculator now, but I will come back to add the actual answer later. Use the formula within the explanation.
What is the period of a simple pendulum 80 cm long a- on earth and b- when it is in a freely falling elevator?
none. when there is gravity T=2pi square root of L/g but in a freely falling elevator, there is no accelerate so it doesn't have period the answer is none
What is the period of a 0.85m long pendulum?
The period of a pendulum can be calculated using the equation T = 2π√(l/g), where T is the period in seconds, l is the length of the pendulum in meters, and g is the acceleration due to gravity (9.81 m/s^2). Substituting the values, the period of a 0.85m long pendulum is approximately 2.43 seconds.
