That will depend on whether you are adding charge to it or taking charge away.
A capacitor charge graph shows how the voltage across a capacitor changes over time when it is connected in an electrical circuit. It illustrates that initially, the voltage across the capacitor rises quickly as it charges up, but eventually levels off as the capacitor becomes fully charged. This graph helps to understand the time it takes for a capacitor to charge and how it behaves in a circuit.
A: It is called discharging a capacitor. The charge will follow the rules of a time constant set up by the series resistor and the capacitor. 1 time constant 63% of the charge will be reached and continue at that rate.
A: from a voltage source a capacitor will charge to 63 % of the voltage in one time constant which is define the voltage source Resistance from the source time capacitor in farads. it will continue to charge at this rate indefinitely however for practical usage 5 time constant is assume to be fully charged
If the resistance is in series with the capacitor, the charge/discharge time is extended.
A capacitor!
To plot a current vs. time graph for a capacitor being charged, you would typically see the current start high and decrease as the capacitor charges up. The rate of decrease in current depends on the capacitance and the resistance in the circuit. To analyze this, you can use the formula for charging a capacitor: I = C(dV/dt), where I is the current, C is the capacitance, and dV/dt is the rate of change of voltage across the capacitor.
In the context of capacitors, the area under a current, I, time, t, graph equals the total charged stored on a capacitor.
Depends upon the capacitance. The time of holding charge can analyse by transient analysis.
It increases. The time constant of a simple RC circuit is RC, resistance times capacitance. That is the length of time it will take for the capacitor voltage to reach about 63% of a delta step change. Ratio-metrically, if you double the resistance, you will double the charge or discharge time.
A: A voltage source Will charge a capacitor to 63% of its input value, The value to get there is stated a Resistance time capacitor as time. Mathematically it will never get there but engineering consider 5 times RC time constant as close enough,
A: Mathematically speaking the capacitor will never charge to the source because it takes one time constant to reach 63% and so on but for practical uses it is assume to be fully charged in 5 time constants R X C = 1 TIME CONSTANT
The charging time of a capacitor is usually lower than the discharging time because during charging, the voltage across the capacitor is increasing from zero to its maximum value, which initially allows a higher current to flow. During discharging, the voltage across the capacitor is decreasing from its maximum value to zero, resulting in a lower current flow. This difference in current flow affects the time it takes for the capacitor to charge and discharge.