(6, 3)
---------points
m = - 5
Y - Y1 = m(X - X1)
------------------------------the form
Y - 3 = - 5(X - 6)
Y - 3 = - 5X + 30
Y = - 5X + 33
----------------------------the equation of the line
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Equation: y-3 = -5(x-6) => y = -5x+33
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
y = 4x - 26
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Slope: -5 Points: (6, 3) Equation: y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
Slope: -3 Point: (4, -5) Equation: y = -3x+7
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept