If: x-2y+12 = 0 then x = 2y-12 or x^2 = (2y-12)^2
If: x^2+y^2 -x -31 = 0 then (2y-12)^2 +y2 -(2y-12)-31
Expanding brackets: 4y^2 -48y +144+y^2 -2y+12-31 = 0
Collecting like terms: 5y^2 -50y+125 = 0
Divide all terms by 5: y^2 -10y+25 = 0
Factorizing the above quadratic equation: (y-5)(y-5) = 0 meaning y =5
Therefore by substitution point of contact is made at: (-2, 5) and that the line is a tangent to the circle.
The point is (-2, 5).
A tangent of a circle is a straight line that touches the circle at only one point.
It works out that the tangent line of y -3x -5 = 0 makes contact with the circle x^2 +y^2 -2x +4y -5 = 0 at the coordinate of (-2, -1) on the coordinated grid.
A tangent to a circle is a line from a point outside the circles which touches the circle at a single point.
the answer is a Tangent.
A tangent line touches the circumference of a circle at just one point but it does not intersect the circle.
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
A tangent is a straight line that touches a circle's circumference at one point
a tangent is a line that touches the circle at only ONE point
A tangent of a circle is a straight line that touches the circle's circumference at just one point
A tangent.
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
A tangent of a circle is a straight line that touches the circle's circumference at just one point.