Tin(IV) = Sn4+
Chloride = Cl-
Formula = SnCl4
Tin (IV) Chloride
Sn4+
When Tin and chlorine combine it creates either:-SnCl2, called tin(II) chloride, stannous chloride. This is molecular in the gas phase and forms polymeric covalent chains in the solid (mp. 247 anhydrous form)), but dissolves to form Sn2+ which may hydrolyse. The electronegativity difference is only 1.2 so it would be expected to be covalent rather than ionic.A covalent molecular compound SnCl4, tin(IV) chloride, stannic chloride, tin tetrachloride.
Tin (IV) phosphide
Sn4+ is the symbol for Tin(IV), that is, the element tin with a oxidation state of 4.
Tin (IV) Chloride
That is Tin (II) Chloride. Sn is Tin and the suffix for Chlorine is nearly always Chloride. The (II) means the Tin [in a hypothetical situation where the compound was purely ionic] has an oxidation state of 2, or +2, (ie deficient of two electrons) Source: A2 Chemistry Student.
how many proton and electron are in the tin IV ion
The formula for the tin four ion is Sn+4
SnCl4
SnCl4
Sn4+
lead IV chloride
Is in the Chemical Compound with the formula SnCl4, called Tin(IV) Chloride. However, Tin IV is actually just tin in a specific oxidation state. It would be better to think of it as Sn4+
A Stannic ion is the ion of Tin(IV). Its formula is Sn4+ . Here tin is in its highest oxidation state of +4. The other ion is Stannous(Sn2+).
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
It is Tin(II) oxide or Stannous oxide