(22.99 g/mol Na / 58.43 g/mol NaCl ) x 100 ppm NaCl= 39.35 ppm Na
No 100 ppm of NaCl = 100 mg NaCl/1 L = 67,87 ppm (67,87 mg/L) of Na
The mean concentration of iodine in sea water is 0,064 ppm.
The answer is 11,5 mg NaCl for 1 L water.
The TDS of sea water is very high (30,000-50,000 ppm) which depends on location and weather.
mm is unit of length, ppm is a non-SI unit of concentration.
Dissolve 50 mg NaCl pro analysis in 1 L demineralized water, at 20 0C, in a volumetric flask.
1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl
Because sea water contain many salts (especially NaCl) and other impurities, dissolved or suspended.
Water (H2O) and Salt (NaCl) with small amounts of Calcium
Salt (NaCl) is extracted from mines or sea water.
Sodium Chloride or NaCl is a naturally occurring salt. When NaCl is mixed with water it disassociates into Na+ cations and Cl- anions.