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0.505l=0.000505m3

20 C=293 K

The gas constant is 8.314 J.K−1·mol−1

Using the idea gas law

PV=nRT

P*0.000505=0.108*8.314*293

Therefore P=520966.76 Pa

Which equals 5.2bar

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Q: What is the pressure in the atmospheres of a 0.108 mole sample of helium gas at a temperature of 20 celsius if its volume is 0.505L?
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