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What statements is true about vapor pressure?
The vapor pressure of 1 m sucrose (C12H22O11) is higher than the vapor pressure of 1 m NaCl where the solvent is water Sea water has a lower vapor pressure than distilled water. The vapor pressure of 0.5 m NaNO3 is the same as the vapor pressure of 0.5 m KBr, assuming that the solvent in each case is water The vapor pressure of 0.10 m KCl is the same as the vapor pressure of 0.05 m AlCl3 assuming the solvent in each case is water The vapor pressure of 1 m NaCl is lower than the vapor pressure of 0.5 m KNO3, assuming that the solvent in each case is water The vapor pressure of 0.10 m NaCl is lower than the vapor pressure of 0.05 m MgCl2 assuming the solvent in each case is water.
Would you feel more pressure 5 m underwater in a pool or 2 m underwater in the lake?
You would feel more pressure 5 m underwater in the pool because the weight of the water above you increases with depth. The pressure in the lake at 2 m would be less than at 5 m in the pool due to the difference in water depth.
What is gauge pressure at a depth of 100 m in water?
The gauge pressure at a depth of 100 m in water can be calculated using the formula P = ρgh, where P is pressure, ρ is density of the fluid, g is the acceleration due to gravity, and h is the depth. Assuming the density of water is 1000 kg/m^3 and taking g as 9.81 m/s^2, the gauge pressure at 100 m depth in water can be found as P = 1000 kg/m^3 * 9.81 m/s^2 * 100 m = 981,000 Pa = 981 kPa.
What is the pressure exerted by a water bed with dimensions of m x m which is 30 cm thick?
To calculate the pressure exerted by a water bed, you can use the formula for pressure: ( P = \frac{F}{A} ), where ( F ) is the force (weight of the water) and ( A ) is the area of the bed. The volume of water in the bed is ( A \times 0.3 ) m (30 cm), and the weight of the water can be calculated using the density of water (approximately 1000 kg/m³). Thus, the pressure is ( P = \frac{\text{density} \times \text{gravity} \times \text{height}}{1} = 1000 , \text{kg/m}^3 \times 9.81 , \text{m/s}^2 \times 0.3 , \text{m} ), yielding a pressure of approximately 2943 Pa (Pascals) regardless of the surface area, as pressure remains constant.
What is the pressure 100 m below the surface of the sea water of denisty 1150kg m 3?
The pressure at 100 meters below the surface of sea water with a density of 1150kg is 145.96 psi.
True or false The vapor pressure of 1 m sucrose is higher than the vapor pressure of 1 m NaCl where the solvent is water?
maybe
Where is water pressure greater at depth of 1 m in a large lake or at a depth of 2 m in a small pond?
The water pressure would be greater at a depth of 2 m in a small pond because the weight of the water above is greater in the pond compared to the lake. The pressure increases with depth as the weight of the water column above applies more force.
Where is the pressure greater . in 10 m below the surface of the sea or 20 m below the surface of the sea?
The pressure is greater at 20 m below the surface of the sea. Pressure increases with depth due to the weight of the water above. Each additional meter of depth adds more pressure, so the pressure will be higher at 20 m compared to 10 m below the surface.
Rank these water solutions in order of increasing vapor pressure?
1. 1 m AlCl3 in water 2. 1 m CaCl2 in water 3. 1 m KCl in water 4. 1 m methanol in water 5. Distilled water 1. 1 m AlF3 in water 2. 1 m MgF2 in water 3. 1 m LiF in water 4. 1 m ethanol in water 5. Distilled water
How many meters of water equals a pressure of 1 psi?
0.7 m
How do you convert meter water column into bar pressure?
Ten meter water column is expressed as a column of water of 1,000 cm high with a section of 1 x 1 cm. This equals 1 dm3 of water which has a mass of 1 kg. As such 10 meter water column exerts a pressure of 1 kg/cm2. 1 kg/cm2 = 0.980665 bar Therefore: 1 m WC = 0.1 kg/cm2 = 0.0980665 bar 0.980665 bar = 1 kg/cm2 = 10 m WC 1 bar = 1.0197162 kg/cm2 = 10.197162 m WC
What is the water pressure at 300 metres?
At a depth of 300 meters in water, the pressure can be calculated using the formula: pressure = depth × density of water × gravitational acceleration. The density of seawater is approximately 1,025 kg/m³, and gravitational acceleration is about 9.81 m/s². Therefore, the pressure at 300 meters is around 3,000 kilopascals (kPa) or 30 times atmospheric pressure, which is roughly equivalent to 30 bar.
