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There is not enough information given. The pressure of a gas in atms equals the number of moles times the kelvin temperature times the 'R' constant (0.0821) divided by the volume. Shorthand, P = nRT/V
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∙ 16y ago
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∙ 11y agoPressure of a gas depends on more than volume. You must also know the temperature and the amount of gas in moles.
PV = nRT is the equation for the Ideal Gas law. R is a constant (like pi for circles).
so if you know all the variable conditions in the equation except pressure, you can solve for pressure.
Wiki User
∙ 9y agoThe Boyle-Mariotte law:
pV = k at constant temperature
The meaning is: if the container with gas is tightly closed and the temperature remain constant the pressure remain unchanged.
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∙ 9y agoAt 60 cm volume the pressure of gas would be 120000 pascals.
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∙ 8y agoThe volume is 20 m3.
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∙ 7y agoThe pressure in at is 0,0041.K.
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What is the mass of a sponge that has a density of 0.25 g cm3 and a volume of 60cm3?
25 g/cm3 x 60 cm3 = 1500 g
Under a pressure of 200 kPa a confined gas has a volume of 2500 cubic meters The pressure acting on the gas is increased to 500 kPa What is the new volume of the gas if the temperature remains t?
p1.V1 / T1 = constant = p2.V2 / T2 (the 'Boyle&Gay-Lussac' Law)250*15/100 = 500*30/ T2T2 = 400K
If a box is 3cm by 2cm by 10 cm how much mass could it hold before if would sink in water?
Volume = 3 cm x 2 cm x 10 cm = 60 cm3 Mass of 60 cm3 water = 60 grams Mass of box + contents would be >60 gramsbefore it could sink.
What happens to volume if the temperature of a gas is decreased from 60 degrees Celsius to 30 degrees Celsius?
The volume of the gas will decrease. The gas molecules move faster when they are warmer, because more heat equates to more energy. The faster they move, the more space they will take up and the greater the volume. Therefore, if the temperature goes down, they have less energy and take up less space. This is shown in the ideal gas law: PV = nRT P = Pressure of the gas V = Volume n = mols of the gas R = ideal gas constant (8.314 J/molK) T = Temperature As you can see, if temperature is decreased and only pressure is allowed to change, with all other variables remaining constant, volume will also have to decrease to maintain the proportion.
One liter is equal to how many kilogram?
0.737 kg. The answer is correct but i tell the calculation density=mass/volume density of petrol at 60*f=737.22 kg/cm3 1 litre=1000 cm3 (1 cm3=1/1000 litre) 737.22(kg/cm3)=mass(kg)/volume(cm3) 737.22(kg/cm3) * volume(cm3)=mass 737.22 * (1/1000 litre)=mass(kg) 0.737 kg=mass There is no conversion. One is volume and the other is mass or weight.
What is the mass of a sponge that has a density of 0.25 g cm3 and a volume of 60cm3?
25 g/cm3 x 60 cm3 = 1500 g
The pressure acting on 60 cubic meters of gas is raised from 236 kPa to 354 kPa The temperature is kept constant What new volume does the gas occupy?
8. Two cubic meters of a gas at 30 degrees Celsius are heated at a constant pressure until the volume doubles. What is the final temperature of the gas? 60.
What is the volume of a cuboid 10cm by 3cmby 2cm?
10*3*2 = 60 cm3
Two cubic meters of a gas at 30 degrees Kelvin are heated at a constant pressure until the volume doubles. What is the final temperature of the gas?
60
What is the density of a substance if it has a mass of 60.00 g and displaces water from a volume of 15.0 ml?
You will mean 15 cc or cubic centimeter. The answer is 4g / cc ( 60 g divide 15 cc )
What is the volume of a prism whose dimensions are 5cm x 3cm x 4cm?
5*3*4 = 60 cm3
How many cubes of edge 2 cm in cuboids 10cmx6cmx8cm?
Volume of cube = 2*2*2 = 8 cm3 Volume of cuboid = 10*6*8 = 480 cm3 So number of cubes in cuboid = 480/8 = 60
Under a pressure of 200 kPa a confined gas has a volume of 2500 cubic meters The pressure acting on the gas is increased to 500 kPa What is the new volume of the gas if the temperature remains t?
p1.V1 / T1 = constant = p2.V2 / T2 (the 'Boyle&Gay-Lussac' Law)250*15/100 = 500*30/ T2T2 = 400K
If a box is 3cm by 2cm by 10 cm how much mass could it hold before if would sink in water?
Volume = 3 cm x 2 cm x 10 cm = 60 cm3 Mass of 60 cm3 water = 60 grams Mass of box + contents would be >60 gramsbefore it could sink.
100 centimeters long 60 centimeters wide 40 centimeters high and the volume of water in it is 3000 centimeters3 how do you find the depth of the water?
depth = 3000/(100*60) = 0.5 cm 3000 cm3 = 3 liters total capacity = 100*60*40 = 240000 cm3 = 240 liters
What if gas is in a sealed container has a pressure of 50 k pa at 300 k what will the pressure be if the temperature rises 360 k?
60kpa
What happens to volume if the temperature of a gas is decreased from 60 degrees Celsius to 30 degrees Celsius?
The volume of the gas will decrease. The gas molecules move faster when they are warmer, because more heat equates to more energy. The faster they move, the more space they will take up and the greater the volume. Therefore, if the temperature goes down, they have less energy and take up less space. This is shown in the ideal gas law: PV = nRT P = Pressure of the gas V = Volume n = mols of the gas R = ideal gas constant (8.314 J/molK) T = Temperature As you can see, if temperature is decreased and only pressure is allowed to change, with all other variables remaining constant, volume will also have to decrease to maintain the proportion.
