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What is the assay method for oxalic acid?

The assay method was developed by using high performance liquid chromatography. The plasma is separated by passing through an ultra filter.


Could you prepare oxalic acid by adding HCl to a solution of sodium oxalate cooling it to room temp and filtering the resulting mixture?

No we cannot prepare Oxalic acid by the given method. Solubility of Sodium Oxalate is less in comparison to solubility of Oxalic acid. So whatever oxalic acid is formed will remain in the solution and cannot be precipitated out in the form of solid


What is the forumla for oxalic acid?

Oxalic acid is H2C2O4


Does Rhubarb have acid in it?

no Oxalic acid is found in rhubarb


What happens when oxalic acid goes into the mouth?

Oxalic acid is found in such plants such as spinach and other plants like rhubarb. In high concentrations oxalic acid is poisonous. Oxalic acid is a organic compound that is colorless.


What elements are in an oxalic acid?

Oxalic acid contain hydrogen, oxygen carbon.


What is formula for oxalic acid?

The formula for Oxalic acid is C2O2(OH)2


What foods have oxalic acid?

Some foods, such as rhubarb and spinach, are high in oxalic acid


Is rhubarb an alkali?

It is an acid - Oxalic acid


Does aqueous ammonia react with oxalic acid?

Yes, aqueous ammonia can react with oxalic acid to form the ammonium salt of oxalic acid, which is ammonium oxalate. This reaction involves the exchange of ions between ammonia and oxalic acid molecules.


Is oxalic acid a strong acid?

No, oxalic acid is considered a weak acid. It dissociates partially in water to release hydrogen ions.


Calculate the required amount of oxalic aciddihydrate to prepare 200 mL of 0.50M oxalic acid solution?

To prepare 200 mL of 0.50M oxalic acid solution, you would need 0.1 moles of oxalic acid. Since oxalic acid is a dihydrate (H2C2O4·2H2O), you would need to account for the water content. The molar mass of oxalic acid dihydrate is 126.07 g/mol, so you would need 12.607 grams of oxalic acid dihydrate to prepare the solution.