0
Calculate the required amount of oxalic aciddihydrate to prepare 200 mL of 0.50M oxalic acid solution?
6
What else can I help you with?
What Calculate mass of potassium chloride required to prepare its 40 solution in 100g of water?
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
How many grams of I2 should be added to 750 g o C Cl4 to prepare a 020 m solution?
To prepare a 0.20 M solution of I2 in CCl4, you would need to calculate the moles of I2 required first. Molarity (M) = moles of solute / liters of solution. Since you know the molarity and volume of the solution, you can calculate the moles of I2 required and then convert that to grams using the molar mass of I2.
What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare?
To prepare 500 mL of a 0.5 M solution of acetic acid, you would need to take 100 mL of the 2.5 M stock solution and dilute it to 500 mL. This is because the molarity equation (M1V1 = M2V2) can be used to calculate the volume of stock solution needed for dilution.
How do you prepare 0.05N of HCl?
To prepare 0.05N HCl solution, you would need to calculate the amount of concentrated hydrochloric acid solution (typically 37% concentration) needed to dilute with water to get the desired concentration. Measure the appropriate volume of the concentrated acid and dilute it with the required amount of water to achieve a final volume of 1 liter.
What mass is required to make 2N solution of Na2co3 calculate mass of sodim carbonate which will be dissolved in 500 ccc?
To prepare a 2N solution of Na2CO3 in 500 mL, you would need to dissolve 42.97 grams of Na2CO3. This is calculated by first converting N to molarity (2N = 2 moles/L), then using the molar mass of Na2CO3 (105.99 g/mol) to calculate the required mass.
What Calculate mass of potassium chloride required to prepare its 40 solution in 100g of water?
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
How many grams of I2 should be added to 750 g o C Cl4 to prepare a 020 m solution?
To prepare a 0.20 M solution of I2 in CCl4, you would need to calculate the moles of I2 required first. Molarity (M) = moles of solute / liters of solution. Since you know the molarity and volume of the solution, you can calculate the moles of I2 required and then convert that to grams using the molar mass of I2.
What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare?
To prepare 500 mL of a 0.5 M solution of acetic acid, you would need to take 100 mL of the 2.5 M stock solution and dilute it to 500 mL. This is because the molarity equation (M1V1 = M2V2) can be used to calculate the volume of stock solution needed for dilution.
Prepare a working solution from a stock solution?
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
How do you prepare 0.05N of HCl?
To prepare 0.05N HCl solution, you would need to calculate the amount of concentrated hydrochloric acid solution (typically 37% concentration) needed to dilute with water to get the desired concentration. Measure the appropriate volume of the concentrated acid and dilute it with the required amount of water to achieve a final volume of 1 liter.
How many mg of Magnesium will reqiured to prepare 60ml of 20 percent solution?
To calculate the mass of magnesium needed, use the formula: mass of solute = volume of solution (ml) x percentage concentration / 100. In this case, it would be 60 ml x 20% = 12 g or 12,000 mg of magnesium will be required to prepare 60 ml of a 20% solution.
What mass is required to make 2N solution of Na2co3 calculate mass of sodim carbonate which will be dissolved in 500 ccc?
To prepare a 2N solution of Na2CO3 in 500 mL, you would need to dissolve 42.97 grams of Na2CO3. This is calculated by first converting N to molarity (2N = 2 moles/L), then using the molar mass of Na2CO3 (105.99 g/mol) to calculate the required mass.
How would you prepare a 1 mole solution of dimethoxyhydroxyacetophenone?
To prepare a 1 mole solution of dimethoxyhydroxyacetophenone, you would dissolve 166.21 grams of the compound in enough solvent to make a total volume of 1 liter. Calculate the required weight based on the molar mass of dimethoxyhydroxyacetophenone (C10H12O4).
How do you prepare 50 mM Sulphuric acid solution?
To prepare a 50 mM Sulphuric acid solution, you would need to calculate the required volume of concentrated Sulphuric acid (typically 96-98%) needed to dilute in water to achieve the desired concentration. You can use the formula: C1V1 = C2V2, where C1 is the concentration of the concentrated acid, V1 is the volume of concentrated acid needed, C2 is the desired concentration (50 mM), and V2 is the final volume of the solution you want to prepare.
What volume of a 2.5M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50M acetic acid solution?
To prepare the 0.50M acetic acid solution, you can use the formula C1V1 = C2V2. Plugging in the values, you get (2.5M)(V1) = (0.50M)(100.0mL). Solving for V1 gives V1 = 20.0 mL. Therefore, 20.0 milliliters of the 2.5M stock solution is required to prepare 100.0 milliliters of the 0.50M acetic acid solution.
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
How many l of 2m solution is required to prepare 3L of 1.2m solution?
To prepare a 3 L solution of 1.2 M, you need a total of 3 L × 1.2 M = 3.6 moles of solute. A 2 M solution contains 2 moles of solute per liter, so to find the volume required, use the formula: volume = moles/concentration. Thus, 3.6 moles ÷ 2 M = 1.8 L of the 2 M solution is needed to prepare 3 L of the 1.2 M solution.
