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Does the mole of solution is equal to mole of solute plus mole of solution?
No, the mole of solution is not equal to the mole of solute plus the mole of solvent. The mole of solution refers to the total amount of moles in a given volume of solution, which includes both the solute and the solvent.
How do you prepare ammonium molybdate?
Ammonium molybdate is (NH4)2MoO4. Its molar mass is 148g/mol. A 0.5M solution will have half a mole per liter of water. Half a mole of ammonium molybdate is 74g, so you would measure out 74g of it, and dissolve it in a liter of water.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
What weights of Bovine Serum Albumin molecular weight 66000 are required to give solutions of 10ml and 100ml volumes containing 1mole of BSA?
To prepare a 10ml solution containing 1 mole of BSA (Molecular weight 66000 g/mol), you would need 66g of BSA. To prepare a 100ml solution containing 1 mole of BSA, you would need 660g of BSA. Remember to adjust the volume accordingly after dissolving the BSA to ensure accurate concentration.
What is the osmolarity of a 0.1 mole sodium chloride solution?
One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.
How do you prepare 1n solution?
Dissolve 1.0 mole gas (17 gram) in 1.0 Liter water
Does the mole of solution is equal to mole of solute plus mole of solution?
No, the mole of solution is not equal to the mole of solute plus the mole of solvent. The mole of solution refers to the total amount of moles in a given volume of solution, which includes both the solute and the solvent.
What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?
To prepare a 1N NaOH solution, you would need to dissolve 40 grams of NaOH in water to make 1 liter of solution. This amount is used because 1N solution means 1 mole of NaOH per liter of solution, and the molar mass of NaOH is 40 g/mol, so 40 grams of NaOH is needed to have 1 mole in 1 liter of solution.
How do you prepare ammonium molybdate?
Ammonium molybdate is (NH4)2MoO4. Its molar mass is 148g/mol. A 0.5M solution will have half a mole per liter of water. Half a mole of ammonium molybdate is 74g, so you would measure out 74g of it, and dissolve it in a liter of water.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
What weights of Bovine Serum Albumin molecular weight 66000 are required to give solutions of 10ml and 100ml volumes containing 1mole of BSA?
To prepare a 10ml solution containing 1 mole of BSA (Molecular weight 66000 g/mol), you would need 66g of BSA. To prepare a 100ml solution containing 1 mole of BSA, you would need 660g of BSA. Remember to adjust the volume accordingly after dissolving the BSA to ensure accurate concentration.
How can you prepare 0.01M KCL solution in 1liter?
To prepare a 0.01M KCl (potassium chloride) solution in 1 liter, you would need to dissolve 0.74 grams of KCl in enough water to make 1 liter of solution. This can be calculated using the formula: moles = Molarity x Volume (in liters) x Molecular weight of KCl.
What is the osmolarity of a 0.1 mole sodium chloride solution?
One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.
How do you prepare a solution of 1 M HClO4?
To prepare a 1 M solution of perchloric acid (HClO4), you would need to dissolve 1 mole of HClO4 in enough water to make a final volume of 1 liter. This can be calculated by using the formula: moles = Molarity (M) x Volume (L). Please handle perchloric acid with caution and use appropriate safety measures while preparing the solution.
How do you prepare a 35mM solution of methanesulfonic acid?
Concentrated MSA is 1.481 g/mole MW = 98.11 g/mole 4.5 mL of concentrated MSA to total volume 2 L gives ~ 35 mM 4.5 mL Conc MSA x 1.481 g/mL / 96.11 g/mole x 1000 mM/mole / 2L = 35 mM
How would you prepare a 1 mole solution of lactose?
Find out the molecular weight of LactoseAdd that many grams of Lactose into a 1000ml volumetric flaskMake up the volume to 1000ml with waterYour 1 Molar solution of Lactose is ready---------------The molar mass of lactose is 342,3 g/mol; the solubility of lactose is 216 g/L at20 0C. Consequently you cannot prepare a molar solution of lactose.
How do you prepare one normal solution of potassium nitrate?
To prepare one normal solution of potassium nitrate, you would dissolve 101.1 grams of potassium nitrate in enough water to make 1 liter of solution. This solution will have a concentration of 1 mole per liter, which is considered a normal solution. Make sure to use a balance to accurately measure the mass of potassium nitrate and a volumetric flask to ensure a final volume of 1 liter.
