100%
The year MUST start on a Sunday. For a leap year, it can start on Saturday or Sunday. In any period of 400 years there are 303 non-leap years, of which 43 begins and ends with a Sunday, and there are 97 leap years, of which 28 begins with a Saturday or a Sunday. So the probability in a non-leap year is 43/303, or 14.2%. And the probability in a leap year is 28/97, or 28.9%
A leap year is 52 weeks plus 2 days. That means that 2 days have 53 instances. So there is a 2/7 chance that there will be 53 Fridays. There is absolutely no chance that there are 54 Sundays, since 53 is the most you can have. Good luck. The exact probability is 28/97, which is about 28.87%.
probability = 2/7 to be exact, 28/97 (about 28.87%)
A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.
Total number of days in a leap year is 366, ie 52 weeks and 2 days. The last 2 days can be either ( Mon Tue, Tue Wed, Wed Thu, Thu Fri, Fri Sat, Sat Sun, Sun Mon) The possible outcomes are 7 The outcomes where one of the day is a Sunday is 2 So probability of getting 53 Sundays is = 2/7. The exact probability is 28/97, which is about 28.87%.
52 unless 1 or 2 January is a Sunday - in which case, 53.
Birthdays are not distributed uniformly over a year but if, for the sake of probability games you assume that they are, then ignoring leap years, the probability is 0.5687. Including leap years, it is slightly lower.
Zero. Each year is either 52 weeks and 1 day, or 52 weeks and 2 days (Leap Year). So no year is 52 weeks and so probability = 0.
Since you are selecting only among leap years, either the first or the second day of the year would have to be a Saturday, so you have two chances out of seven (a probability of 2/7) that there are 53 saturdays.
If you assume that birth dates are uniformly distributed over the year (they are not), and you ignore leap years, then the probability of two people selected at random, share a birthday is 1/365.
you divide 366 by 2 and you get 183 days that is half of a leap year
A leap year has 52 weeks and 2 days.