10,000,000 to one.
1 in 4,782,969
49/9000
It depends on how the game is structured, a piece of information that was not given in the answer... If the numbers are reused, then there are 1 x 107 (ten billion, in the short scale) permutations. Without combinations, then, the probability is 1 x 10-7. If the numbers are not reused, and we are playing combinatorial, in the style of most state sponsored lotteries, then the number of combinations is (10-3)! / 7!, which is 120, making the probability 1 in 120, or about 0.00833. There are other possibilities but, again, it depends on the rules, and you did not specify them completely.
There is 100% chance.
A number is drawn and compared with your Pokémon. If the ID of the Trainer who first got that Pokémon matches one or more of the last digits of the chosen number, you win a prize. You can increase your chances of winning by trading with lots of people.
Nothing, unless all the others match up in the proper order.
If the last 3 digits match you get exp share. The more IDs you have in your boxes the higher chance you have of winning
None of the digits can be 10, so the probability is 0.
You can get another Master Ball by winning the ID Lottery in Jubilife City with all matching digits, trading for a Pokemon holding it, or using an Action Replay.
The answer is 9*9!/9*109 = 0.0003629 approx.
The "Pick 3" lottery game typically involves selecting three digits from 0 to 9. The probability of correctly guessing the exact combination is 1 in 1,000, as there are 1,000 possible combinations (000 to 999). If the order of the digits matters and you want to consider different arrangements, the probability remains the same for a standard game format. However, variations in rules can affect these odds, so it's essential to check the specific game's guidelines.
How many permutations of 3 different digits are there, chosen from the ten digits 0 to 9 inclusive?