The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
The product of reacting ether with NaOH followed by HCl is an alcohol. The initial reaction with NaOH would form an alkoxide ion, which is then protonated by HCl to give the alcohol as the final product.
The product of Ni (nickel) reacting with HCl (hydrochloric acid) is typically nickel chloride (NiCl2) and hydrogen gas (H2).
The product equation for the reaction between HCl (hydrochloric acid) and BTB (bromothymol blue) results in a color change from blue to yellow. The equation is: HCl + BTB (blue) → H+ (colorless) + Cl- + BTB (yellow)
The reaction of K2CO3 and HCl typically produces KCl (potassium chloride), H2O (water), and CO2 (carbon dioxide).
HCl + NaOH -------> NaCl + H2O
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
The product of reacting ether with NaOH followed by HCl is an alcohol. The initial reaction with NaOH would form an alkoxide ion, which is then protonated by HCl to give the alcohol as the final product.
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The product of Ni (nickel) reacting with HCl (hydrochloric acid) is typically nickel chloride (NiCl2) and hydrogen gas (H2).
Beryllium is soluble in HCl; the product of reaction is the beryllium chloride, BeCl2.
The product equation for the reaction between HCl (hydrochloric acid) and BTB (bromothymol blue) results in a color change from blue to yellow. The equation is: HCl + BTB (blue) → H+ (colorless) + Cl- + BTB (yellow)
The reaction of K2CO3 and HCl typically produces KCl (potassium chloride), H2O (water), and CO2 (carbon dioxide).
Hydrochloride means the product has a "salt" component in its chemical makeup. Dilaudid is hydromorphone hcl ( hydromorphone hydrochloride)
The chemical equation for the reaction of triethylamine (C6H15N) with HCl (hydrochloric acid) is: C6H15N + HCl -> C6H15NH+Cl-
No, ZnCl2 does not react with dilute HCl because ZnCl2 is already a product of the reaction between zinc metal and HCl. So, no further reaction occurs when ZnCl2 is added to dilute HCl.
When ethanamide reacts with sodium nitrite and HCl, it produces N-nitrosoethanamide.