Hydrated Iron (III) oxide:
2Fe + 1.5O2 + xH2O -> Fe2O3·xH2O
where x is the number of H2O molecules present.
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The chemical equation is:4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
the product of an equation is the multiples made by them
The product is water:2 H2 + O2 = 2 H2O
The reactions are:4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)2 FeO(OH) -------Fe2O3 + H2O
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
c2h5oh+h2o
1
The chemical equation is:4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
2f2+2h2o>>4hf+o2
the product of an equation is the multiples made by them
The product is water:2 H2 + O2 = 2 H2O
2h2s+o2-->2h2o+co2
2NaH2 + O2 yields 2Na + 2H2O