Hydrated Iron (III) oxide:
2Fe + 1.5O2 + xH2O -> Fe2O3·xH2O
where x is the number of H2O molecules present.
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The product is water:2 H2 + O2 = 2 H2O
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
The balanced chemical equation for the reaction C2H6 + O2 → CO2 + H2O is: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
C5H12 + 8 O2 --> 5 CO2 + 6 H2O (1 mol O2)(6 mol H2O/8 mol O2) = 0.75 mol H2O
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The product is water:2 H2 + O2 = 2 H2O
The product of the reaction between hydrogen peroxide (H2O2) and manganese dioxide (MnO2) is oxygen gas (O2) and water (H2O).
When hydrogen gas (H2) reacts with oxygen gas (O2), they combine to form water (H2O) as a product. This reaction releases energy in the form of heat and light.
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
2NaH2 + O2 yields 2Na + 2H2O
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
The balanced chemical equation for the reaction C2H6 + O2 → CO2 + H2O is: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
This simple equation is: 2H2 + O2 = 2H2O
C5H12 + 8 O2 --> 5 CO2 + 6 H2O (1 mol O2)(6 mol H2O/8 mol O2) = 0.75 mol H2O
The product for the reaction between PbO2 and O2 is PbO2.