NO reaction , because of the Common Ion effect. Both substances have chloride (Cl^-) ions.
When BaCl2 reacts with HCl, a double displacement reaction occurs where the Ba2+ and Cl- ions from BaCl2 switch places with the H+ and Cl- ions from HCl, forming BaCl2 and HCl. The resulting products are BaCl2 and HCl.
The reaction between barium chromate (BaCrO4) and hydrochloric acid (HCl) produces barium chloride (BaCl2), chromium(III) chloride (CrCl3), and water (H2O). The balanced chemical equation for this reaction is: BaCrO4 (s) + 2HCl (aq) -> BaCl2 (aq) + CrCl3 (aq) + H2O
Test for the anions,according to your word,i think you got the salts,so, use these reagents HCL,BACL2,Adding bacl2 and Hcl to Naso4-white ppt observed in soluble,but barium chloride will give no ppt...so probem solved
The chemical equation for hydrochloric acid reacting with barium carbonate is: HCl + BaCO3 -> BaCl2 + CO2 + H2O. This reaction produces barium chloride (BaCl2), carbon dioxide (CO2), and water (H2O) as products.
Ba(OH)2(aq) + H2SO4(aq) ---> BaSO4(s) + 2H2O(l)
When BaCl2 reacts with HCl, a double displacement reaction occurs where the Ba2+ and Cl- ions from BaCl2 switch places with the H+ and Cl- ions from HCl, forming BaCl2 and HCl. The resulting products are BaCl2 and HCl.
The reaction between barium chromate (BaCrO4) and hydrochloric acid (HCl) produces barium chloride (BaCl2), chromium(III) chloride (CrCl3), and water (H2O). The balanced chemical equation for this reaction is: BaCrO4 (s) + 2HCl (aq) -> BaCl2 (aq) + CrCl3 (aq) + H2O
Test for the anions,according to your word,i think you got the salts,so, use these reagents HCL,BACL2,Adding bacl2 and Hcl to Naso4-white ppt observed in soluble,but barium chloride will give no ppt...so probem solved
The chemical equation for hydrochloric acid reacting with barium carbonate is: HCl + BaCO3 -> BaCl2 + CO2 + H2O. This reaction produces barium chloride (BaCl2), carbon dioxide (CO2), and water (H2O) as products.
Ba(OH)2(aq) + H2SO4(aq) ---> BaSO4(s) + 2H2O(l)
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
HCl and CuO form CuCl2 and H2O, BaCl2 does not react with CuCl2 so it may react with water so the precipitate are of Ba(OH)2 Added: But this is not the case because to dissolve CuO first you'll need a bit more acid to get it completely dissolved. If the solution would become neutral then Cu(OH)2 would precipitate at concentration of [Cu2+] more than 1.6*10-5 (because Ks=1.6*10-19) rather than Ba(OH)2 (Ks=10-10)
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
HCl + NaOH -------> NaCl + H2O
To balance any chemical equation, first ensure that you have the correct formulae for all the reactants and products:BaCl2 + H2SO4 ------> BaSO4 + HClThen work methodically through the equation, making sure that there are the same numbers of each element present on either side of the equation.In this case, we need an extra chlorine on the right hand side, and an extra hydrogen on the RHS, so the result?BaCl2 + H2SO4 -------> BaSO4 + 2HCl
Ba(OH)2 (aq) + 2HCl (aq) --> BaCl2 (aq) + 2H2O (l)
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.