Na + MgCl2 ----> NaCl + Mg is the chemical equation so yes
yes mgcl2 is aqous solution
Mg + MgCl2
MgCl2 Mg = 24.30 2Cl = 70.906 FW = 95.21 (Remember SigFigs) 12.5g ÷ 95g of MgCl2 = 0.131 moles of MgCl2 200mL = 0.200 L 0.131 moles of MgCl2 ÷ 0.200 L = 0.656 Molar Concentration
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
Your question appears to lack some necessary detail. Sodium is Na Magnesium Chloride is MgCl2 "What is the equation for sodium and magnesium chloride?" = Na + MgCl2 Is that what you are asking or do mean what is the equation for sodium ___x___ and magnesium chloride? Magnesium chloride appears commercially as a solution in water from 0-35% MgCl2, or an anhydrous solid 98% MgCl2 or hexahydrate solid 47% MgCl2. What is the form of sodium you are trying to use? NaOH? NaCl? ??
Na + MgCl2 ----> NaCl + Mg is the chemical equation so yes
Na + MgCl2 ----> NaCl + Mg is the chemical equation so yes
MgO + 2HCl =MgCl2 +H2O
Mg + 2HCl --> MgCl2 + H2 Like that. Salt and hydrogen gas product.
Mg(s) + 2HCl(aq) ---> MgCl2(aq) + H2(g)
NA
MgCl2 is magnesium chloride.
MgCl2=95grams per mole so 105g/95g is 1.10 mols of MgCl2
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
The synthesis equation for MgCl2 is Mg + Cl2 -> MgCl2. The decomposition reaction is MgCl2 - heat-> Mg + Cl2.
MgCl2