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What is the radius of the semicircle in a cyclotron if deutron where m equals 3.3410-27 kg acquires 15 meV energy given B equals 1.5 T?
Wiki User
∙ 10y ago
Well, here's how I would do it, if I really had to:
Radius = (mass) x (speed)/(charge) x (B)
Speed = Sqrt(2 x KE/mass)
Deuteron mass = 3.341 x 10-27 kg
Deuteron charge = 1.6 x 10-19 Coul
1 meV = 1.6 x 10-13 Joule
KE = 15 meV = 2.4 x 10-12 Joule
B = 1.5 Tesla = 15,000 Gauss = 1.5 Weber/meter2
Radius = Sqrt(2 x KE x mass)/(charge) x(B)
Radius = Sqrt(2 x 2.4 x 10-12 x 3.341 x 10-27)/(1.6 x 10-19) x (1.5)
Radius = 52.77 centimeters(rounded)
(Since v2/c2 is only 0.016, I took the easy way out and didn't apply
any relativistic correction to the mass.)
Wiki User
∙ 10y ago
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